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Effectus [21]
3 years ago
6

The contour plot of is shown below. determine if the given quantity in each part is positive, negative, or zero.

Mathematics
1 answer:
Reptile [31]3 years ago
7 0
There is no contour plot shown below.
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Z +6 divided by 1/3 = 4
Allushta [10]

Hey there!!

z + 6 / 1/3 = 4

z + 6 = 4 × 1/3

z + 6 = 4/3

z = 4/3 - 6

z = 4 - 18 / 3

z = -14/3

Hope it helps!

7 0
3 years ago
Who is 5 times 3 related to 5 / 1/3
olya-2409 [2.1K]

Answer:

5 times 3 and 5 divide by 1/3  yield the same result - see below.

Step-by-step explanation:

When we divide by a fraction we invert it and then multiply so:

5 / 1/3

= 5 * 3/1

= 5 * 3.

3 0
3 years ago
100 points!! <br> Please solve question 50 in detail
SCORPION-xisa [38]

Answer:

2.62

Step-by-step explanation:

log_{b} \frac{b^{2}x^{\frac{5}{2} }}{\sqrt{y}}

First, write the square root as exponent.

log_{b} \frac{b^{2}x^{\frac{5}{2} }}{y^{\frac{1}{2}}}

Move the denominator to the numerator and negate the exponent.

log_{b}(b^{2}x^{\frac{5}{2}}y^{-\frac{1}{2}})

Use log product property.

log_{b}(b^{2}) + log_{b}(x^{\frac{5}{2}}) + log_{b}(y^{-\frac{1}{2}})

Use log exponent property.

2 log_{b}(b) + {\frac{5}{2}}log_{b}(x) - {\frac{1}{2}}log_{b}(y)

Substitute values.

2(1) + \frac{5}{2}(0.36) - \frac{1}{2}(0.56) \\2.62

4 0
3 years ago
Read 2 more answers
Chicken Delight claims that 87% of its orders are delivered within 10 minutes of the time the order is placed. A sample of 80 or
jeka57 [31]

Answer:

There is strong evidence that less than 87% of the orders are delivered in less than 10 minutes.

Decision rule: Reject the null hypothesis if (P-value < level of significance)

Test statistic z=-2.70

Decision: Reject the null hypothesis (0.003<0.010)

Step-by-step explanation:

In this question we have to test an hypothesis.

The null and alternative hypothesis are:

H_0: \pi\geq0.87\\\\H_a:\pi

The significance level is assumed to be 0.01.

The sample of size n=80 gives a proportion of p=61/80=0.7625.

The standard deviation is:

\sigma=\sqrt{\frac{\pi(1-\pi)}{N} }=\sqrt{\frac{0.87*0.13}{80} }=0.0376

The statistic z is then

z=\frac{p-\pi+0.5/N}{\sigma}=\frac{0.7625-0.87+0.5/80}{0.0376} } =\frac{-10125}{0.0376} =-2.70

The P-value is

P(z

The P-value (0.003) is smaller than the significance level (0.010), so the effect is significant. The null hypothesis is rejected.

There is strong evidence that less than 87% of the orders are delivered in less than 10 minutes.

Decision rule: Reject the null hypothesis if (P-value < level of significance)

Test statistic z=-2.70

Decision: Reject the null hypothesis (0.003<0.010)

6 0
3 years ago
Please help with my geometry
faust18 [17]

Answer:

www.mahtpapa.com

Step-by-step explanation:

5 0
2 years ago
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