<h3>
Answer:</h3>
48.95% (m/v)
<h3>
Explanation:</h3>
From the question we are given;
- Mass of solute, NaCl is 186 g
- Volume of the solvent, water as 3.80 L or 380 mL
We are required to calculate the mass volume percent of solution;
How do we calculate the mass volume percent of a solution?
- To calculate the mass volume percent, we use the formula,
Mass volume percent = (mass of solute in g/Volume of solvent in mL) 100
= (186 g ÷ 380 mL)100
= 48.95%
Therefore, the mass volume percent of a NaCl solution is 48.95% (m/v).
This answer would be primary consumers
By looking at a property chart and figuring out what will become from certain elements
Chemical Bonding, my dude.
Answer:
48.84mL
Explanation:
H2SO4 + 2KOH → K2SO4 + 2H2O
From the question:
nA = 1
nB = 2
From the question given we obtained the following information:
Ma = 0.43M
Va =?
Mb = 0.35M
Vb = 120mL
Using MaVa / MbVb = nA/nB, we can easily find the volume of the acid required. This is illustrated below:
MaVa / MbVb = nA/nB
0.43 x Va / 0.35 x 120 = 1/2
Cross multiply to express in linear form
2 x 0.43 x Va = 0.35 x 120
Divide both side by the (2 x 0.43)
Va = (0.35 x 120) /(2 x 0.43)
Va = 48.84mL
Therefore, the volume of H2SO4 required is 48.84mL