Given :
Molarity of acetic acid solution, M = 0.10 M.
pKa of acetic acid, pKa = 4.75 .
To Find :
Percentage dissociation of 0.10 M solution of acetic acid.
Solution :
We know, 
Taking antilog both side, we get :
Since, acetic acid has 1 hydrogen atom to loose , so it is a monoprotic acid.
Now, percentage dissociation of monoprotic acid is given by :
Hence, this is the required solution.
Answer:
i can't read it.. maybe upload a visible picture?
Answer: The smallest unit of matter.
Explanation:
The answer to this question is that <span>the strong base will require less HCl to bring the pH to 7 than the weak base.
The string base ionizes completely so the [OH-] will be neutralized faster. The weak base has an equilibrium that will constantly shift</span> to compensate for any [OH-] loss, meaning more HCl will be needed to titrate it to lower pH.
