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LUCKY_DIMON [66]
3 years ago
13

If sin theta=-square root 3 over 2 and pie

Mathematics
1 answer:
choli [55]3 years ago
7 0

Answer:cos theta = -(1)/2; tan theta = sqrt(3)

cos theta = -(1)/2; tan theta = -1

cos theta = (sqrt(3))/4; tan theta = -2

cos theta = 1/2; tan theta = sqrt(3)

cos theta = 4/3

Step-by-step explanation:

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Please solve this ..................​
AlladinOne [14]

Answer:

Step-by-step explanation:

√20=√5*2*2

√20=2√5

4 0
2 years ago
A basketball court is in the shape of a rectangle. It has a length of (x - 7) meters and a width of (x + 3) meters:
Molodets [167]

Answer:

x2 - 4x - 21

Step-by-step explanation:

Area = (x -7 )(x +3)

= x*x - 7*x + x*3 - 7*3

=x2 - 4x - 21

5 0
2 years ago
Evaluate the expression and enter your answer below.
jeka94

Answer:

The answer is 9.

Step-by-step explanation:

PEMDAS (Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction)

3x10+15-6^2

3x10+15-36

30+15-36

45-36

9

7 0
2 years ago
Read 2 more answers
To the nearest tenth of a degree, find the sizes of the acute angles in the 7-24-25 right
fiasKO [112]
First of all, just to avoid being snookered by a trick question, we should verify that these are really right triangles:

7² + 24² really is 25² , and 8² + 15² really is 17² , so we're OK there.

In the first one:
sin(one acute angle) = 7/25 = 0.28
the angle = sin⁻¹ (0.28)  =  16.26°
the other acute angle = (90° - 16.26°)  = 73.74° 

In the second one:
sin(one acute angle) = 8/17 = 0.4706...
the angle = sin⁻¹  (0.4706...)  =  28.07°
the other acute angle =  (90° - 28.07°) = 61.93°


I'm sorry, but just now, I don't know how to do the 
third triangle in the question.
7 0
3 years ago
Solve each of the following equations using a method other than the Quadratic Formula.
liraira [26]

Answer:

A)

y^2-6y = 0

or, y(y-6) = 0

or, y = 0 or y = 6

B)

n^2+5n+7 = 7

or, n^2+5n+7-7 = 7-7 ( Subtracting 7 from both sides)

or, n^2+5n = 0

or, n(n+5) = 0

or, n=0 or n= -5

C)

2t^2-14t+3 = 3

or, 2t^2-14t = 0

or, 2t(t-7) = 0

or, t=0 or t=7

D)

1/3x^2+3x-4 = -4

or, 1/3x^2+3x = 0

or, 1/3x(x+9) = 0

or, x=0 or x= -9

E)

Zero is a common solution to each of the equations. This is because each of the equations had a variable outside the parenthesis with an operation of multiplication.

THANK YOU FOR READING.

8 0
2 years ago
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