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My name is Ann [436]

3 years ago

5

Providing that it does not collide with another object, what is the most likely reason that an object moving through space would

change velocity?

1 answer:

Ronch [10]3 years ago

4 0

<em>GRAVITY !</em>

The object doesn't have to collide or even TOUCH something else in order to feel a gravitational force toward it.

If there's a gravitational force between the space object and ANYTHING else, (and there always is !), then that force will change the object's speed or direction of motion.

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You want to make a photo album for your friend. In three to five sentences, describe at least one advantage and one disadvantage

DanielleElmas [232]

Answer:

if it were to be digital then you would be able to carry it around where ever and look at it to remind you of the memories, however it probably wouldnt last as long as the physical one. eg if you phone breaks there is a chance to restore the photo but you would had to have backed it up beforehand.

4 0

2 years ago

Read 2 more answers

How is a scientific law different than a scientific theory ?

OLga [1]

Answer: scientific law is the description of an observed phenomenon. It doesn't explain why the phenomenon exists or what causes it. The explanation of a phenomenon is called a scientific theory

hope this helps

plz mark brainleist

3 0

3 years ago

Compute the dot product of the vectors u and v, and find the angle between the vectors. Bold v equals 7 Bold i minus Bold j and

OLga [1]

Answer:

$\theta = 106.3 degree$

Explanation:

As we know that

$\vec w = -\hat i + 7\hat j$

$\vec v = 7\hat i - \hat j$

also we know that

$\vec v. \vec w = -14$

it is given as

$\vec v. \vec w = (-\hat i + 7\hat j).(7\hat i - \hat j)$

$\vec v. \vec w = - 7 - 7 = -14$

also we can find the magnitude of two vectors as

$|v| = \sqrt{(-1)^2 + (7)^2}$

$|v| = \sqrt{50}$

similarly we have

$|w| = \sqrt{(7^2) + (-1)^2}$

$|w| = \sqrt{50}$

now we know the formula of dot product as

$\vec v. \vec w = |v||w| cos\theta$

$-14 = (\sqrt{50})^2cos\theta$

$\theta = cos^{-1}(\frac{-14}{50})$

$\theta = 106.3 degree$

3 0

2 years ago

A published hypothesis:

kow [346]

Answer:

should be tested by the scientific community

4 0

2 years ago

Please help Need good grade

ivann1987 [24]

Answer:

The other angle is 120°.

Explanation:

Given that,

Angle = 60

Speed = 5.0

We need to calculate the range

Using formula of range

$R=\dfrac{v^2\sin(2\theta)}{g}$ ...(I)

The range for the other angle is

$R=\dfrac{v^2\sin(2(\alpha-\theta))}{g}$ ....(II)

Here, distance and speed are same

On comparing both range

$\dfrac{v^2\sin(2\theta)}{g}=\dfrac{v^2\sin(2(\alpha-\theta))}{g}$

$\sin(2\theta)=\sin(2\times(\alpha-\theta))$

$\sin120=\sin2(\alpha-60)$

$120=2\alpha-120$

$\alpha=\dfrac{120+120}{2}$

$\alpha=120^{\circ}$

Hence, The other angle is 120°

6 0

3 years ago