Answer:
has more energy, has a greater amplitude, has a higher frequency
Explanation:
I believe D is ur answer..................
Answer:
500 THz .
Explanation:
Velocity of light in air = 3 x10⁸ m /s
wave length of light = 600 nm
= 600 x 10⁻⁹ m
= 6 x 10⁻⁷ m
frequency in air = velocity in air / wave length in air
= 3 x 10⁸ / 6 x 10⁻⁷
= .5 x 10¹⁵ Hz
= 5 x 10¹⁴Hz
= 500 x 10¹² Hz
= 500 THz
When light enters the medium of gem , its wavelength and velocity changes in such a way that its frequency remains constant. So in the medium of gem also its frequency remains 500 THz .
Answer:
The speed of electron is
and the speed of proton is 2468.02 m/s.
Explanation:
Given that,
Electric field, E = 560 N/C
To find,
The speed of each particle (electrons and proton) 46.0 ns after being released.
Solution,
For electron,
The electric force is given by :


Let v is the speed of electron. It can be calculated using first equation of motion as :

u = 0 (at rest)



For proton,
The electric force is given by :


Let v is the speed of electron. It can be calculated using first equation of motion as :

u = 0 (at rest)



So, the speed of electron is
and the speed of proton is 2468.02 m/s. Therefore, this is the required solution.