Answer:
Final speed of security car v = 65 m/s
Explanation:
Given:
Speed of race car u1 = 35m/s
Speed of security car u2 = 5 m/s
Acceleration = 5 m/s²
Find:
Final speed of security car v
Computation:
Assume, they chase S meter
So
S = u1t + [1/2]at²
S = 35t
S = u2t + [1/2]at²
so,
35t = 5t + [1/2](5)t²
t = 12 s
So
v = u + at
v = 5 + 5(12)
Final speed of security car v = 65 m/s
They would all strike the ground at the same time. If air resistance is neglected for example in an airless tube, then gravity is the only force acting on them and it has the same effect on them dropping so the drop at the same speed.
Answer:
18,000 j
Explanation:
the lightbulb dissipates 5W of power
P = ΔE / Δt
rearrange to solve for energy
ΔE = PΔt
P = 5W
t = 1 hour = 60 minutes = 3600 seconds
ΔE = 5 * 3600
ΔE = 18000 J
Answer:

Explanation:
From the question, acceleration from
in 10 seconds.
Acceleration function can be written as:-

From the acceleration equation, we can obtain the velocity equation:

We calculate velocity after 10sec from the above v(t) as
.
To obtain distance travelled after 10 seconds:-

Therefore 200m is for 10seconds, and next 200m at 30m/s
Total time=
Answer:
it will take for the sphere to increase in potential by 1500 V, 503.71 s.
Explanation:
The charge on the sphere after t seconds is:
q = (1.0000049 - 1.0000000) t = 0.0000049 t
The voltage on the surface is
V = k *
= k 0.0000049 t / R
solve for t
t = (R*V) / (0.0000049 k) = (0.12 * 1500) / (0.0000049 *
) = 503.71 s