The amount of water given is a control. D) because, if a plant grows bigger as a result of the water, and not the sun this would disrupt the experiment.
Answer:
t_1 = 0.5*pi*sqrt( m / k )
Explanation:
Given:
- The block of mass m undergoes simple harmonic motion. With the displacement of x from mean position is given by:
x(t) = A*cos(w*t)
Find:
- At what time t1 does the block come back to its original equilibrium position (x=0) for the first time?
Solution:
- The first time the block moves from maximum position to its mean position constitutes of 1/4 th of one complete cycle. So, the required time t_1 is:
t_1 = 0.25*T
- Where, T : Time period of SHM.
- The time period for SHM is given by:
T = 2*pi*sqrt ( m / k )
Hence,
t_1 = 0.25 * 2 * pi * sqrt( m / k )
t_1 = 0.5*pi * sqrt( m / k )
Answer:
option (b)
Explanation:
Let both teh springs are extended by y.
For first spring
m1 x g = k1 x y
where, m1 is the mass of first ball and k1 be the spring constant of first spring
.... (1)
For second spring
m2 x g = k2 x y
where, m2 is the mass of second ball and k2 be the spring constant of second spring
.... (2)
The frequency of the body is given by

So, from equation (1) and equation (2), the ratio of k is to m is same, so the frequency of both the balls is same.