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Oksi-84 [34.3K]
3 years ago
8

A wheelbarrow can be used to help lift a load, such as a pile of dirt, and then push the load across a distance. A man pushes a

wheelbarrow.
Physics
2 answers:
Bumek [7]3 years ago
5 0

Answer:

B.) a wheel and axle and a lever

Explanation:

skelet666 [1.2K]3 years ago
4 0

Answer:

B.) a wheel and axle and a lever

Explanation:

P.S - The exact question is -

Given - A wheelbarrow can be used to help lift a load, such as a pile of dirt, and then push the load across a distance. A man pushes a wheelbarrow.

To find - Which simple machines make up a wheelbarrow?

A.) a pulley and an inclined plane

B.) a wheel and axle and a lever

C.) a pulley and a wheel and axle

D.) a lever and a wedge

Proof -

The correct option is - B.) a wheel and axle and a lever

Wheelbarrows are used to carry more goods from place to place by using minimal force as compared when goods are carried by hand.

With this machine, During hauling people can save time.

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Calculate the centripetal force on the end of a 100 m (radius) wind turbine blade that is rotating at 0.5 rev/s. Assume the mass
Alja [10]

Answer:

3947.6 N

Explanation:

Centripetal Force: This is the force that tend to moves a body towards the center of a circle during circular motion.

The formula for centripetal force is

F = mω²r ........................ Equation 1

Where F = Centripetal force, ω = angular velocity, r = radius.

Where π = 3.1415

Given: m = 4 kg, ω = 0.5 rev/s = (0.5×2π) rad/s = 3.1415 rad/s, r = 100 m.

Substitute into equation 1

F = 4(3.1415)²(100)

F = 3947.6 N

Hence the centripetal force on the turbine blade = 3947.6 N

6 0
3 years ago
Calculate the speed of an object that moves 200 m in 4 s?
Rasek [7]
50m/s

I divided the 200m by 4s (so 200/4) to get 50m per second
7 0
3 years ago
What is the acceleration of a 10kg mass pushed by a 5N force?​
GenaCL600 [577]

Answer:

<h2>0.5 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

From the question we have

a =  \frac{5}{10} =  \frac{1}{2}   \\  = 0.5

We have the final answer as

<h3>0.5 m/s²</h3>

Hope this helps you

5 0
3 years ago
So far, you’ve been working with an "ideal" pulley system. How do you think real pulley systems are different, and how would tha
almond37 [142]

Answer:

In an ideal pulley system is assumed as a perfect system, and the efficiency of the pulley system is taken as 100% such that there are no losses of the energy input to the system through the system's component

However, in a real pulley system, there are several means through which energy is lost from the system through friction, which is converted into heat, sound, as well as other forms of energy

Given that the mechanical advantage = Force output/(Force input), and that the input force is known, the energy loss comes from the output force which is then reduced, and therefore, the Actual Mechanical Advantage (AMA) is less than the Ideal Mechanical Advantage of an "ideal" pulley system

The relationship between the actual and ideal mechanical advantage is given by the efficiency of the pulley system as follows;

Efficiency \, \% = \dfrac{AMA}{IMA}  \times 100

Explanation:

8 0
3 years ago
Please help me find out this answer
Elanso [62]
The direction of work.........

4 0
3 years ago
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