An isolated conducting sphere has a 12 cm radius. One wire carries a current of 1.0000049 A into it while another wire carries a
1 answer:
Answer:
it will take for the sphere to increase in potential by 1500 V, 503.71 s.
Explanation:
The charge on the sphere after t seconds is:
q = (1.0000049 - 1.0000000) t = 0.0000049 t
The voltage on the surface is
V = k * = k 0.0000049 t / R
solve for t
t = (R*V) / (0.0000049 k) = (0.12 * 1500) / (0.0000049 * ) = 503.71 s
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Given :
A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m.
The force of friction between the refrigerator and the floor is 230 N.
To Find :
How much work has been performed by the mover on the refrigerator.
Solution :
Since, refrigerator is moving with constant velocity.
So, force applied by the mover is also 230 N ( equal to force of friction ).
Now, work done in order to move the refrigerator is :
Hence, this is the required solution.
Answer:
The force is 272.73 newtons
Explanation:
We're going to use impulse-momentum theorem that states impulse is the change on the linear momentum this is:
(1)
Impulse is also defined as average force times the time the force is applied:
(2)
By (2) on (1):
solving for :
(3)
We already know Δt is equal to 0.22 s, all we should do now is to find and put on (3) (
the initial momentum and
the final momentum). Linear momentum is defined as
, using that on (3):
(4)
Velocity (v) are vectors so direction matters, if positive direction is the right direction and negative direction left and
so (4) becomes:
(5)
Using (5) on (3):