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3 years ago

What do scientists use to determine what the interior of a moon is like?

Chemistry

1 answer:

polet [3.4K]3 years ago

7 0

Use sound waves, and examine samples of earth, examine meteorites

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(GIVING BRAINLIEST)Match the type of chemical bond with the best description:

Kipish [7]

Answer:

A and 3

B and 2

C and 1

Explanation:

Ionic bonding is the transfer of electrons from a cation to an anion.

Covalent bonding is the sharing of electrons between nonmetal atoms.

Metallic bonding is the sea of electrons metal cations.

Hope this helped!

8 0

2 years ago

Which statement is correct?

sergiy2304 [10]

Answer:

a) is correct.......,.....

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2 years ago

What is the total number of grams of mg consumed when 0.50 mole of h2 is produced

rosijanka [135]

Answer:

12 grams

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4 0

1 year ago

What is alchemy??????!

Salsk061 [2.6K]

the medieval forerunner of chemistry, concerned with the transmutation of matter, in particular with attempts to convert base metals into gold or find a universal elixir.

7 0

2 years ago

Read 2 more answers

When a lead acid car battery is recharged by the alternator, it acts essentially as an electrolytic cell in which solid lead(II)

lesya692 [45]

Answer: The mass of lead deposited on the cathode of the battery is 1.523 g.

Explanation:

Given: Current = 62.0 A

Time = 23.0 sec

Formula used to calculate charge is as follows.

$Q = I \times t$

where,

Q = charge

I = current

t = time

Substitute the values into above formula as follows.

$Q = I \times t\\= 62.0 A \times 23.0 sec\\= 1426 C$

It is known that 1 mole of a substance tends to deposit a charge of 96500 C. Therefore, number of moles obtained by 1426 C of charge is as follows.

$Moles = \frac{1426 C}{96500 C/mol}\\= 0.0147 mol$

The oxidation state of Pb in $PbSO_{4}$ is 2. So, moles deposited by Pb is as follows.

$Moles of Pb = \frac{0.0147}{2}\\= 0.00735 mol$

It is known that molar mass of lead (Pb) is 207.2 g/mol. Now, mass of lead is calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\ 0.00735 = \frac{mass}{207.2 g/mol}\\mass = 1.523 g$

Thus, we can conclude that the mass of lead deposited on the cathode of the battery is 1.523 g.

3 0

2 years ago