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1 year ago

When hydrogen gas is bubbled into 2-butyne, the product is

Chemistry

1 answer:

kolbaska11 [484]1 year ago

3 0

Answer:

On treatement of 2 -with hydrogen gas and lindlar catalyst, the major product obtained is cis-2butene.

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Which group or groups of atoms are the only atoms with f orbitals A. All atoms heavier than barium B. All atoms heavier than kry

Mashcka [7]

Answer:

All atoms heavier than barium

Explanation:

In the periodic table, elements are divided into blocks. We have the;

s- block elements

p- block elements

d- block elements

f- block elements

However, immediately after Barium, we now encounter elements that have f-orbitals. Barium possesses a fully filled d-orbital. Hence after it, we see elements with 4f and 5f orbitals called the Lanthanides and actinides. The elements following the lanthanide and actinide series possess completely filled f-orbitals as inner orbitals.

Hence elements heavier than barium all possess f-orbitals.

6 0

3 years ago

Food can spoil very quickly. Which methods are used to minimize the reactions that allow bacteria and fungi to grow?

Oduvanchick [21]

Answer:

preservatives and low temperature

3 0

3 years ago

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Which of the following (with specific heat capacity provided) would show the smallest temperature change upon gaining 200.0 J of

Brut [27]

Answer: The smallest temperature change is shown by water.

Explanation:

To calculate the heat absorbed or released, we use the equation:

$q=mC\times \Delta T$ ......(1)

where,

q = heat absorbed = 200.0 J

m = mass of the substance

C = specific heat of substance

$\Delta T$ = change in temperature

As, the same amount of heat is getting absorbed in all the cases. So, the change in temperature will depend on the product of mass and specific heat.

For the given options:

Option a: 50.0 g Fe, $C_{Fe}=0.449J/g^oC$

We are given:

$m=50.0g\\C_{Fe}=0.449J/g^oC$

Putting values in equation 1, we get:

$200.0J=50.0g\times 0.449J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{50\times 0.449}=8.99^oC$

Change in temperature = 8.99°C

Option b: 50.0 g water, $C_{water}=4.18J/g^oC$

We are given:

$m=50.0g\\C_{water}=4.18J/g^oC$

Putting values in equation 1, we get:

$200.0J=50.0g\times 4.18J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{50\times 4.18}=0.96^oC$

Change in temperature = 0.96°C

Option b: 25.0 g Pb, $C_{Pb}=0.128J/g^oC$

We are given:

$m=50.0g\\C_{Pb}=0.128J/g^oC$

Putting values in equation 1, we get:

$200.0J=25.0g\times 0.128J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{25\times 0.128}=62.5^oC$

Change in temperature = 62.5°C

Option d: 25.0 g Ag, $C_{Ag}=0.235J/g^oC$

We are given:

$m=25.0g\\C_{Ag}=0.235J/g^oC$

Putting values in equation 1, we get:

$200.0J=25.0g\times 0.235J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{25\times 0.235}=34.04^oC$

Change in temperature = 34.04°C

Option e: 25.0 g granite, $C_{granite}=0.79J/g^oC$

We are given:

$m=25.0g\\C_{Fe}=0.79J/g^oC$

Putting values in equation 1, we get:

$200.0J=25.0g\times 0.79J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{25\times 0.79}=10.13^oC$

Change in temperature = 10.13°C

Hence, the smallest temperature change is shown by water.

5 0

3 years ago

Technetium-104 has a half life of 18.0 minutes. how much of a 165.0 g sample remains after 90.0 minutes?

11Alexandr11 [23.1K]

The mass of 165.0 g sample that remains after 90.0 minutes is 5.16 grams

calculation

lambda㏑2/18= 0.0385

m(t)= 165 x e( 0.0385 x90) =5.16g

8 0

2 years ago

Read 2 more answers

Examine the ph scale below. How does household bleach compare to household ammonia?

Kazeer [188]

Answer is: household ammonia has 10 times higher H⁺ concentration.

1) pH(household ammonia) = 11.5.

pH = -log[H⁺], approximately the negative of the base 10 logarithm of the molar concentration of hydrogen ions.

[H⁺] = 10∧(-pH).

[H⁺] = 10∧(-11.5).

[H⁺] = 3.16·10⁻¹² M; concentration of hydrogen ions.

2) pH(household bleach) = 12.5.

[H⁺] = 10∧(-12.5).

[H⁺] = 3.16·10⁻¹³ M.

3) 3.16·10⁻¹² M / 3.16·10⁻¹³ M = 10.

6 0

3 years ago

Read 2 more answers