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andrezito [222]
2 years ago
7

A student wants to prepare 250.0 mL of a 0.754 M HCl solution, starting with a 11.7 M HCl solution. How much of the 11.7 M HCl s

olution is needed
Chemistry
1 answer:
grin007 [14]2 years ago
5 0
See answer in photo

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vfiekz [6]

Answer:- A) 1 mole of Fe and 1.5 moles of CO_2 .

Solution:- The balanced equation is:

Fe_2O_3+3CO\rightarrow 2Fe+3CO_2

From balanced equation, there is 1:3 mol ratio between Fe_2O_3 and CO,  From given data, 3 moles of  Fe_2O_3 and 1.5 moles of CO are taken for the reaction. CO is the limiting reactant as it's moles are less than the other reactant and which is also clear from the mole ratio. We could do the calculations also to support this. Let's calculate the moles of CO required to react completely with given 3 moles of  Fe_2O_3 .

3molFe_2O_3(\frac{3molCO}{1molFe_2O_3})

= 9 mol CO

So, from calculations, 9 moles of CO are required to react completely with 3 moles of Iron(III)oxide but only 1.5 moles of CO are available. Hence, CO is the limiting reactant and the product moles are calculated from this as:

1.5molCO(\frac{2molFe}{3molCO})

= 1 mol Fe

1.5molCO(\frac{3molCO_2}{3molCO})

= 1.5 mol CO_2

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