Answer:
Lithium hydroxide is a base.
Carbon dioxide is the anhydride of the carbonic acid, H₂CO₃.
Therefore, the reaction awaited is a typical neutralization reaction with the formation of a salt and water.
2LiOH + CO₂ → Li₂CO₃ + H₂O
So, 2*20 = 40 moles of LiOH react with 20 moles of CO₂.
Molar Mass of LiOH = 23.95 g/mol
So, 40 * 23.95 = 958 g
Answer:
See explanation
Explanation:
Let the equation of dissolution be;
AB2(s) ⇄A(aq) + 2S
Hence;
Ksp = [A] [2s]^2
Let the concentration of the species be s
Ksp= s × (2s)^2
Ksp= 4s^3
Since s= 5mol/dm^3
Ksp = 4(5mol/dm^3)^3
Ksp = 500 mol^2dm^-6
Answer:
.334 M
Explanation:
Ca Cl2 is calcium chloride
Ca = 40.078 gm/mole
Cl = 35.45 gm/ mole
40 . 078 + 2 * 35.45 = 110.978 gm/mole for Ca Cl2
28.9 gm / 110.978 gm/mole = .260 moles CaCl2
.260 moles/ .78 liter = .334 M
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According to this formula, when:
ΔG = ΔH - T*ΔS
when the reaction is thermodynamically spontaneous ΔG < 0
∴ ΔH - T* ΔS = 0
∴T*ΔS = ΔH
∴ T = ΔH / ΔS
when we have:
ΔH = -70KJ
and ΔS = -0.4 KJ/K
So by substitution:
T = -70KJ /- 0.4
= 175 K
∴the certain temperature below which the reaction will be thermodynamically spontaneous is 175 K