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andrezito [222]

2 years ago

7

A student wants to prepare 250.0 mL of a 0.754 M HCl solution, starting with a 11.7 M HCl solution. How much of the 11.7 M HCl s

olution is needed

1 answer:

grin007 [14]2 years ago

5 0

See answer in photo

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A 100 W light bulb is placed in a cylinder equipped with a moveable piston. The light bulb is turned on for 2.0×10−2 hour, and t

drek231 [11]

Answer:

(a) ΔU = 7.2x10²

(b) W = -5.1x10²

(c) q = 5.2x10²

Explanation:

From the definition of power (p), we have:

$p = \frac {\Delta W}{\Delta t} = \frac {\Delta U}{\Delta t}$ (1)

<em>where, p: is power (J/s = W (watt)) W: is work = ΔU (J) and t: is time (s) </em>

(a) We can calculate the energy (ΔU) using equation (1):

$\Delta U = p \cdot \Delta t = 100 \frac{J}{s} \cdot 2.0\cdot 10^{-2} h \cdot \frac{3600s}{1h} = 7.2 \cdot 10^{2} J$

(b) The work is related to pressure and volume by:

$\Delta W = -p \Delta V$

<em>where p: pressure and ΔV: change in volume = V final - V initial </em>

$\Delta W = - p \cdot (V_{fin} - V_{ini}) = - 1.0 atm (5.88L - 0.85L) = - 5.03 L \cdot atm \cdot \frac{101.33J}{1 L\cdot atm} = -5.1 \cdot 10^{2} J$

(c) By the definition of Energy, we can calculate q:

$\Delta U = \Delta W + \Delta q$

<em>where Δq: is the heat transfer </em>

$\Delta q = \Delta U - \Delta W = 7.2 J - (-5.1 \cdot 10^{2} J) = 5.2 \cdot 10^{2} J$

I hope it helps you!

6 0

3 years ago

On a molar basis, which is a more effective bleaching agent- kbro3 or naocl?

Aleksandr-060686 [28]

<span>On a molar a basis, the most effective bleaching agent kbro3 has more oxygen, but due to the bromine, it would make things look yellowish. The bromine would counteracts the bleaching effect. As we all know, bleach is naocl or hypochlorite</span>

6 0

3 years ago

Which water source becomes polluted as it travels over the earth?

never [62]

Run off

Explanation:

Run-off are the water sources that becomes polluted as they travel over the earth surface.

Surface run-off are water that moves on the earth surface. This water is a component of the water cycle which usually originate from precipitation.

As the water moves through different terrain it comes into contact with different pollutants.
Some of these run-off travels through mines, waste disposal sites among others.
This leads to the contamination of this form of water as it moves through these earth materials.
They are the most polluted water

Learn more:

Ocean water brainly.com/question/6760255

#learnwithBrainly

8 0

4 years ago

What is a substance?

shusha [124]

I think the answer is C. An element or compound that cannot be physically separated. Sorry if im wrong.

7 0

3 years ago

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In

qaws [65]

The question is incomplete, here is the complete question:

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and water react to form acetylene and calcium hydroxide:

$CaC_2(s)+2H_2O(g)\rightarrow C_2H_2(g)+Ca(OH)_2(s)$

In the second step, acetylene, carbon dioxide and water react to form acrylic acid:

$6C_2H_2(g)+3CO_2(g)+4H_2O(g)\rightarrow 5CH_2CHCO_2H(g)$

Write the net chemical equation for the production of acrylic acid from calcium carbide, water and carbon dioxide. Be sure your equation is balanced.

<u>Answer:</u> The net chemical equation is written below.

<u>Explanation:</u>

The intermediate balanced chemical reaction are:

(1) $CaC_2(s)+2H_2O(g)\rightarrow C_2H_2(g)+Ca(OH)_2(s)$ ( × 6 )

(2) $6C_2H_2(g)+3CO_2(g)+4H_2O(g)\rightarrow 5CH_2CHCO_2H(g)$

To omit acetylene from the net chemical reaction, we multiply Equation (1) by 6.

<u>Equation 1:</u> $6CaC_2(s)+12H_2O(g)\rightarrow 6C_2H_2(g)+6Ca(OH)_2(s)$

<u>Equation 2:</u> $6C_2H_2(g)+3CO_2(g)+4H_2O(g)\rightarrow 5CH_2CHCO_2H(g)$

<u>Net chemical equation:</u> $6CaC_2(s)+3CO_2(g)+16H_2O(g)\rightarrow 5CH_2CHCO_2H(g)+6Ca(OH)_2(s)$

Hence, the net chemical equation is written above.

6 0

3 years ago