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zhuklara [117]
3 years ago
10

Convert each of the measurements given to the new unit stated using the factor label method (dimensional analysis). Show all wor

k including rewriting the given.
One step conversions:

26 cm to m ___________
4 hr to min ___________
3.25 km to m ___________
5 ft to in ___________
Chemistry
1 answer:
jeka943 years ago
8 0

26 cm -0.26 m

4 hr - 240 min

3.25 km -3250 m

5 ft -60 inches

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Helium is most likely to behave as an ideal gas when its under what?
rodikova [14]

Answer:

Low pressure and high temperature :)

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Please rate and mark brainiest!!

7 0
2 years ago
The weight of 100g H2 and 100 g He is same yet the number of elements is not same.​
sukhopar [10]

Answer:

The mole and atonmicity of both the gases are different, the number of atoms is not same.

Explanation:

The number of atoms in a molecule (compound) depends on mole number and atomicity.

↬ Mole of 100 g H₂ = 100g ÷ 2u = 50 mole

∴Number of atoms in 100 g H₂

= 2 x 50 x 6.022 × 10²³

= 6.022 x 10²⁴ atoms

↬ Mole of 100 g He = 100g ÷ 4u = 25 mole

∴ Number of atoms in 100 g He

= 1 × 25 × 6.022 × 10²³

= 150.55 × 10²³

= 1.5055 x 10²⁵ atoms

Thus, The mole and atonmicity of both the gases are different, the number of atoms is not same.

 

<u>-TheUnknownScientist</u><u> 72</u>

6 0
2 years ago
What is true of a solution of 1.0M HCL
Charra [1.4K]

Answer:

What is true of a solution of 1.0 M HCl(aq)? It contains 1.0 gram of HCl per 100 grams of water.

Explanation:

8 0
3 years ago
What is the number of moles of gas contained in a 3 L vessel at 300 K with a pressure of 1.50 atm? (Given: R = 0.08205 L∙atm/mol
Cloud [144]
Use the PV= nRT formula and you’ll get .183 moles
4 0
3 years ago
Uranium-238 decays to lead-206 with a half-life of 4.5 x 109 yr. Determine how much uranium-238 decays in milligrams (to three s
Mamont248 [21]

Answer:

2.15 mg of uranium-238 decays

Explanation:

For decay of radioactive nuclide-

                        N=N_{0}.(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}

where N is amount of radioactive nuclide after t time, N_{0} is initial amount of radioactive nuclide and t_{\frac{1}{2}} is half life of radioactive nuclide

Here N_{0}=4.60 mg, t=4.1\times 10^{9}yr and t_{\frac{1}{2}}=4.5\times 10^{9}yr

So,N=(4.60mg)\times (\frac{1}{2})^{\frac{4.1\times 10^{9}}{4.5\times 10^{9}}}

so, N = 2.446 mg

mass of uranium-238 decays = (4.60-2.446) mg = 2.15 mg

3 0
3 years ago
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