Answer: The numerator and denominator degrees of freedom (respectively) for the critical value of F are <u>4</u> and<u> 118 .</u>
Step-by-step explanation:
We know that , for critical value of F, degrees of freedom for numerator = k-1
and for denominator = n-k, where n= Total observations and k = number of independent variables.
Here, Numbers of independent variables(k) = 5
Total observations (n)= 123
So, Degrees of freedom for numerator = 5-1=4
Degrees of freedom for denominator =123-5= 118
Hence, the numerator and denominator degrees of freedom (respectively) for the critical value of F are <u>4</u> and<u> 118 .</u>
Answer:
Those areas are: A 1 = 12, A 2 = 19
Step-by-step explanation:
The area of shape 1 : it consists of 1 square + 4 right triangles
Area of the square: A = a², area of the triangle: A = 1/2 · a · h
A 1 = 2² + 4 · 1/2 · 2 · 2 = 4 + 8 = 12
The area of shape 2 : it consists of 2 isosceles triangles
A 2 = 1/2 · 2 · 4 + 1/2 · 6 · 5 = 4 + 15 = 19
Given that <span>the weights of farmer carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1 ounces.
The probability of a normally distributed data between two values (a, b) is given by:
</span>
Domain is the set of input values whilst range is the set of output values. i think 3x is your domain and -3 +1 is your domain
Answer:
x=-17/19, y=131/19. (-17/19, 131/19).
Step-by-step explanation:
-19x=26-9
-19x=17
x=-17/19
9(-17/19)=54-9y
-153/19=54-9y
9y=54-(-153/19)
9y=54+153/19
9y=1026/19+153/19
9y=1179/19
y=(1179/19)/9
y=(1179/19)(1/9)
y=1179/171
y=131/19
