=58.464 kg/hr
width= 21.0 feet
length= 20.0 feet
snowflake mass=1.60 milligrams
1 foot^2=1450 snowflakes per minute
area of lawn=length*width
area=(21.0)(20.0)
area=420 feet^2
1450 snowflakes at 1.60 milligrams per snowflake:
(1.60)(1450)=2320 milligrams
2320 milligrams to kilograms:
=(2320 mg)(1 gram/1000 mg)(1 kilogram/1000 grams)
=(2320)(1/1000)(1/1000)
=(2.32)(1/1000)
=0.00232 kg per minute
0.00232 kg per minute to kg per hour:
=(0.00232 kg/1 minute)(60 minutes/1 hour)
=(0.00232)(60)
=0.1392 kg per hour per square foot
For the total lawn's accumulation in kilograms per hour, multiply by area:
=(0.1392 (kg/hr) per 1 foot^2)(420 feet^2)
=58.464 kilograms of snow accumulate on the lawn per hour
Answer:
The object A will be having the greater density compared to object B.
Explanation:
It is known that density of any object is defined as the mass of any object occupying a given volume. So the ratio of mass and volume will help to determine the density of any object.
From the above equation, it can be seen that the density of any object is directly proportional to the mass of the object and inversely proportional to the volume occupied by the object.
So in the present context, the mass of objects A and B are same and it is 100 g. Thus, the density of object A and object B will be influenced by their volume. As it is given that the volume of object A is 50 cm3 and object B is 100 cm3, then depending upon the relationship of volume and density, the density of both the objects can be determined. As the object with higher volume will be having lesser density as volume is inversely proportional to density. Thus, in the given case the volume of object B is greater than object A and so the object A will be having greater density compared to object B.
Pretty sure it’s b! mark as brainliest
4 mutations occured, as four letter we're different 25 million years later. Over one hundred years we can expect it to mutate at the sane rate, but 4 times longer. 4 time 4 is 16 mutations over 100 million years