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Slav-nsk [51]
2 years ago
13

SKJIEDHISJLKDSKSJKA HELPP

Chemistry
1 answer:
Vinil7 [7]2 years ago
6 0

Answer:

agree

disagree

agree

hope it help u

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Which phase is heat energy being released?
scZoUnD [109]

The answer is B
Vaporization
6 0
2 years ago
You leave a piece of bread outside for a few days. It forms green and blue mold. It smells awful. A chemical change has occurred
Fed [463]

False. It is a physical change because the molecules of the bread didn't change only the form of the bread changed.

3 0
3 years ago
Read 2 more answers
You are asked to write observations about a 100g sample of Nitrogen-16 before it decays, but you're running late. In order to ma
san4es73 [151]

Answer:

You cannot make observations if you are 57 seconds late into the lab.

Explanation:

The atomic nucleus can split by decay into 2 or more particles as a result of the instability of its atomic nucleus due to the fact that radioactive elements possess an unstable atomic nucleus.

Now, the primary particles which are emitted by radioactive elements in order to make them decay are alpha, beta & gamma particles.

The half life equation is;

N_t = N₀(½)^(t/t_½)

Where:

t = duration of decay

t_½ = half-life

N₀ = number of radioactive atoms initially

N_t = number of radioactive atoms remaining after decay over time t

We are given;

t = 57 secs

N₀ = 100 g

Now, half life of Nitrogen-16 from online sources is 7.2 seconds. t_½ = 7.2

Thus;

N_t = 100(1/2)^(57/7.2)

N_t = 0.4139g

We are told that In order to make observations, you require at least .5g of material.

The value of N_t you got is less than 0.5g, therefore you cannot make observations if you are 57 seconds late.

5 0
2 years ago
How much heat would need to be absorbed for 40g of ice to melt?
Eddi Din [679]

Answer:

- 19501130 dhakdjsu dhakdjsu 2

Explanation:

3 0
3 years ago
If 100.0g of nitrogen is reacted with 100.0g of hydrogen, what is the excess reactant? What is the limiting reactant? Show your
Drupady [299]

N₂ : limiting reactant

H₂ : excess reactant

<h3>Further explanation</h3>

Given

mass of N₂ = 100 g

mass of H₂ = 100 g

Required

Limiting reactant

Excess reactant

Solution

Reaction

<em>N₂+3H₂⇒2NH₃</em>

mol N₂(MW=28 g/mol) :

\tt mol=\dfrac{mass}{MW}=\dfrac{100}{28}=3.571

mol H₂(MW= 2 g/mol) :

\tt mol=\dfrac{100}{2}=50

A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients, and small or exhausted reactans become a limiting reactants

From the equation, mol ratio N₂ : H₂ = 1 : 3, so :

\tt \dfrac{3.571}{1}\div \dfrac{50}{3}=3.571\div 16.6

N₂ becomes a limiting reactant (smaller ratio) and H₂ is the excess reactant

5 0
2 years ago
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