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Slav-nsk [51]
2 years ago
13

SKJIEDHISJLKDSKSJKA HELPP

Chemistry
1 answer:
Vinil7 [7]2 years ago
6 0

Answer:

agree

disagree

agree

hope it help u

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There are many minerals which contain silver. A 2.00 g sample of one of these, stephanite, is placed in water and all of its sil
Nata [24]

Answer:

68.3%

Explanation:

First, let us look at the equation of reaction involving silver and magnesium chloride:

2Ag + MgCl2 ----> 2AgCl + Mg

1 mole of MgCl2 is required to precipitate 2 moles of Ag completely from the solution. That is a ratio of 1 to 2.

Now, mole of MgCl2 used to precipitate all the Ag

             = molarity x volume

                      = 2.19 M x 2.89/1000

                         = 0.0063291 mole

Since 1 mole of MgCl2 would always require 2 moles of Ag, 0.0063291 mole will therefore require:

      0.0063291 x 2 = 0.0126 mole of Ag

This means that 0.0126 mole of Ag is present in stephanie.

Mass of silver in stephanie = mole x molar mass

                              = 0.0126 x 107.8682

                                      = 1.365 g

Thus, 1.365 g of silver is present in 2.00 g sample of stephanie.

Mass percent of silver in stephanie = 1.365/2.00 x 100

                                         = 68.25% = 68.3% to the correct number of significant figure.

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