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umka2103 [35]
2 years ago
10

7 years ago father was 7 times as old as his son was. three years hence, he will be three times as old as his son find their pre

sent ages.​
Mathematics
1 answer:
EastWind [94]2 years ago
8 0

Answer:

son = 10 , father = 40

Step-by-step explanation:

Let Five years ago the age of son be x years and age of father be 7x years

Present age of son =x+5

Present age of father =7x+5

5 years later their age will (x+10) and (7x+10)

∴7x+10=3(x+10)

7x−3x=20

4x=20

x=5

So, the present age of son=x+5=5+5=10years

and the present age of father=7x+5=35+5=40years

hope it helps you

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4 0
3 years ago
getting home from trick or treat celia and emma counted their candies. half of celias candies is equal to 2/3 of emmas candies.
blagie [28]

Candies with celias and emmas is 60 and 45 respectively.

<u>Solution:</u>

Given, Getting home from trick or treat celia and emma counted their candies.  Half of celias candies is equal to 2/3 of emmas candies.  

They had a total of 105 candies altogether.  

We have to find how many candies did each of them have.

Let the number of candies with celias be n, then number of candies with emma will be 105 – n.

Now according to given condition.

\begin{array}{l}{\frac{1}{2} \times \text { celias candies count }=\frac{2}{3} \times \text { emmas candies count }} \\\\ {\rightarrow \frac{1}{2} \times n=\frac{2}{3} \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 n=4(105-n)} \\\\ {\quad \rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n+4 n=420} \\\\ {\rightarrow 7 n=7 \times 60} \\\\ {\rightarrow n=60}\end{array}

Hence, candies with celias and emmas is 60 and 45 respectively.

4 0
3 years ago
ON YOUR OWN:
qwelly [4]

Answer:

125 defective jeans

Step-by-step explanation:

We are told that;

During inspections, 5 defective pairs of jeans are found in a shipment of 200 pairs of jeans .

We are supposed to determine the number of defective jeans in a shipment of 5000 pairs, if the trend continues.

Therefore;

5 defective = 200 pairs

What about in 5000 pairs?

Number of defective pairs = (5000 × 5 ) ÷ 200

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Thus, in a shipment of 5000 pairs of jeans there will be 125 defective pairs

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