Question

7 years ago father was 7 times as old as his son was. three years hence, he will be three times as old as his son find their present ages.​

Answer 1

Answer:

son = 10 , father = 40

Step-by-step explanation:

Let Five years ago the age of son be x years and age of father be 7x years

Present age of son =x+5

Present age of father =7x+5

5 years later their age will (x+10) and (7x+10)

∴7x+10=3(x+10)

7x−3x=20

4x=20

x=5

So, the present age of son=x+5=5+5=10years

and the present age of father=7x+5=35+5=40years

hope it helps you