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Valentin [98]
3 years ago
14

jasmine sells girl scout cookies for $4 dollars a box jasmine says if sells $265 boxes she will make 2,000 dollars. is the exact

answer reasonablezc
Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
8 0
What you do is you mulitply 4 times 265 which is 1060! So the exact answer is not reasonable!
Nina [5.8K]3 years ago
3 0
No because 4•200 =1060
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On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)
Aloiza [94]

The perimeter of the kite is (10 + 2√53) units if the kite and the coordinates of the kite are point W is at (-3, 3), point X is at (2, 3), point Y is at (4, -4), and point Z is at (-3, -2).

<h3>What is quadrilateral?</h3>

It is defined as the four-sided polygon in geometry having four edges and four corners. Kite is quadrilateral, in which. Two pairs of congruent sides, and it has one pair of opposite congruent angles.

The figure is missing.

On a coordinate plane, kite WXYZ is shown (please refer to the picture)

We have a kite and the coordinates of the kite are:

Point W is at (-3, 3), point X is at (2, 3), point Y is at (4, -4), and point Z is at (-3, -2).

Using the distance formula we can find the distance between coordinates:

\rm d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance between W and X:

\rm WX=\sqrt{(2+3)^2+(3-3)^2}

WX = 5 units

Similarly, distance between X and Y:

XY = √53 units

YZ = √53 units

ZW = 5 units

Perimeter = sum of the all sides

Perimeter = 5 + √53 + √53 + 5

Perimeter = (10 + 2√53)  units

Thus, the perimeter of the kite is (10 + 2√53) units if the kite and the coordinates of the kite are point W is at (-3, 3), point X is at (2, 3), point Y is at (4, -4), and point Z is at (-3, -2).

Learn more about the quadrilateral here:

brainly.com/question/6321910

#SPJ1

4 0
1 year ago
Which set of decimals are in the correct order from smallest to largest?
77julia77 [94]

Answer:

A

Step-by-step explanation:

8 0
2 years ago
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
NemiM [27]

Answer:

a) 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

b) 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 373 minutes and standard deviation 67 minutes. So \mu = 373, \sigma = 67

A) What is the probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes?

So n = 5, s = \frac{67}{\sqrt{5}} = 29.96

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 373}{29.96}

Z = 1.23

Z = 1.23 has a pvalue of 0.8907.

So there is a 1-0.8907 = 0.1093 = 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

Lean

Normally distributed with mean 526 minutes and standard deviation 107 minutes. So \mu = 526, \sigma = 107

B) What is the probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes?

So n = 5, s = \frac{107}{\sqrt{5}} = 47.86

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 526}{47.86}

Z = -2.42

Z = -2.42 has a pvalue of 0.0078.

So there is a 1-0.0078 = 0.9922 = 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

7 0
3 years ago
PLEASE HELP ASAP WILL MARK BRAINLIEST
luda_lava [24]

Answer:

x=11

Step-by-step explanation:

7x-9-4(x-1)=28

7x-9-4x+4=28

3x-5=28

3x=33

x=11

4 0
3 years ago
Which statement about the graph of f(x)=e^x is true?Please Help
Elina [12.6K]
It does not crosses any axises. 3rd case is true. I passes through the point 1, e
4 0
3 years ago
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