Assuming Hardy-Weinberg equilbrium, we have
p + q = 1
where p = frequency of dominant allele and q = frequency of recessive allele. So
p = 1 - q = 1 - 0.04 = 0.96
Consequently we have
• p² = 0.9216 = frequency of hom ozygous domininant genotype
• pq = 0.0768 = frequency of heterozygous genotype
• q² = 0.0016 = frequency of hom ozygous recessive genotype
since
p² + 2pq + q² = 1
Answer:
this was sooooo long ago i forgot how to do this
Explanation:
Answer:
D. Longshore currents
Explanation:
Longshore currents are characterized as the sediment transport that occurs in the surf zone, due to the oblique incidence of the waves, along the beach. A current develops between the beach and the surf zone parallel to the coast, normally between 0.3 and 1 m / s. It is this process that is responsible for accumulating and removing sand that results in displacement of barrier islands.
