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3 years ago

What is the volume of 18.0 M concentrated HCl solution that must be diluted in order to make 250mL of a 2.00 M HCl solution?

Chemistry

1 answer:

blagie [28]3 years ago

5 0

Answer:

The answer to your question is: V1 = 27.8 ml of HCl 18 M

Explanation:

Data

HCl = [18M]

HCl Vol = ?

HCl = [ 2M]

HCl vol = 250 ml

Formula

V₁ C₁ = V₂ C₂

V₁ = V₂ C₂ / C₁

Process (substitution)

V₁ = (250)(2) / 18

V₁ = 500 / 18

V1 = 27.8 ml

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2 years ago

Oxidation of methane

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2 years ago

If a gas occupies 1532.7 mL at standard temperature, what volume does it occupy at 49.4 ºC if the pressure remains constant?

ElenaW [278]

Answer:

a. 1810mL

Explanation:

When conditions for a gas change under constant pressure (and the number of molecules doesn't change), it follows Charles' Law:

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$ where the temperatures must be measured in Kelvin

To convert from Celsius to Kelvin, add 273, or use the equation: $T_C+273=T_K$

For this problem, one must also recall that standard temperature is 0°C (or 273K).

So, $T_1 = 273[K]$ , and $T_2 = (49.4+273)[K]=322.4[K]$ .

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

$\dfrac{(1532.7[mL])}{(273[K])}=\dfrac{V_2}{(322.4[K])}$

$\dfrac{(1532.7[mL])}{(273[K\!\!\!\!\!{-}])}(322.4[K\!\!\!\!\!{-}] )=\dfrac{V_2}{(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})$

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1 year ago

One beaker contains 19.93 mL, another contains 14.0 mL and a third contains 10.6 mL. What is the total volume of the three beake

Juli2301 [7.4K]

Answer:

$\large \boxed{\text{44.5 mL}}$

Explanation:

When adding or subtracting values, you must round your answer to the same "place" as the measurement with its last significant figure furthest to the left.

That is, you round off to the same number of decimal places as the measurement with the fewest decimal places.

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The measurements of 14.0 and 10.6 have one digit after the decimal point, so you round the sum to have only one digit to the right of the decimal.

The number to be dropped (3) is less than 5, so you drop it.

$\text{The total volume of the three beakers is $\large \boxed{\textbf{44.5 mL}}$}$

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3 years ago

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