Given,
The two isotopes of B are 10B and 11B
% abundance of 10B = 19.80
% abundance of 11B = 80.20
Average atomic mass of B
= 
= 
= 
= 
= 10.802
Therefore, the average atomic mass of B is 10.802 u
12 carbon atoms<span>, 22 hydrogen atom, and 11 oxygen atoms in 2 moles of sucrose</span>
Answer:
0.95L
Explanation:
Data obtained from the question include:
V1 (initial volume) = 1L
T1 (initial temperature) = 315K
P1 (initial pressure) = 1.10 atm
T2 (final temperature) = stp = 273K
P2 (final pressure) = stp = 1atm
V2 (final volume) =?
Using the general gas equation P1V1/T1 = P2V2/T2, the final volume of the system can be obtained as follow:
P1V1/T1 = P2V2/T2
1.1 x 1/315 = 1 x V2/273
Cross multiply to express in linear form.
315 x V2 = 1.1 x 273
Divide both side by 315
V2 = (1.1 x 273) /315
V2 = 0.95L
Therefore, the final volume of the system if STP conditions are established is 0.95L
1 μL = 10^-6 L by definition
So...
82 μL = 82x10^-6 L = 8.2x10^-5 L
