A solid will always hold its shape as long as there are no item/forces acting on it.
Liquids, plasma, and gases will never hold a shape on there own, mostly all liquids only hold the shape there given. Gases never really have a shape.And plasma is a form of energy, so its more like the gas, it has to be given a shape/container.
Answer :B
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Answer:
C. H:C:H:H
Explanation:
Follow these simple steps to correctly draw a Lewis dot structure: Add up the total number of valence electrons found in the entire compound. Draw the simple structure (skeleton structure) of the compound by connecting everything with single bonds only. Add electrons to all the noncentral atoms. Put any unused electrons on the central atom.
Answer:
A five-sided polygon.- cyclopentane
A square.- cyclobutane
A five-sided polygon with one line extending from a point.- methylcyclopentane
A 6-sided polygon with a line extending from one point to a C H 3.- methlcyclohexane
Explanation:
Gold is known to be an element. The term that best describes 10-karat gold is that it is an homogeneous mixture.
- Gold as an element of often has an ideal state of purity where there contains nothing but gold atoms.
A heterogeneous mixture is known to be a mixture that cannot be chemically sound everytime. Gold jewelry is known to be a homogeneous mixture as it is always will look good and remain unchanged for a long time.
As good example of homogeneous products, e.g a 1-kilogram 24-karat gold bar has unique properties.
Learn more about Gold from
brainly.com/question/11083304
Explanation:
Let us assume that the ratio for the given reaction is 1:1.
Therefore, we will calculate the moles of 
as follows.
Moles of solution = molarity × volume (L)
= 0.0440 M × 0.014 L
= 0.000616 moles
Moles of excess EDTA = 0.000616 moles
Also, the initial moles of EDTA will be calculated as follows.
Total initial moles of EDTA = 0.0600 M × 0.025 L
= 0.0015
Therefore, moles of EDTA reacted with 
will be as follows.
= 0.0015 - 0.000616
= 0.00088 moles
Since, we have supposed a 1 : 1 ratio between and EDTA
.
So, moles of = 0.00088 moles
Now, we will calculate the molarity of as follows.
Molarity of solution = 
= 
= 0.015 M
Thus, we can conclude that the original concentration of the solution is 0.015 M.
