<span>11.2G is the answer to this problem.
</span>
Oxygen (6O2) and Glucose (C6H12O6)
<span>Reference: 6CO2 + 6H2O + light energy = C6H12O6 + 6O2.</span>
Here, we should use combined gas law which can be derived from combined gas law, “PV=nRT”. Rearranging, we can get PV/T=nR. Then we can set the two states in the problem together to get
P1V1/T1 = P2V2/T2
Then just plug in and solve algebraically.
Hope this helps
The answer to fill in the blank is (igneous)
I hope I helped.
Answer:
u will equate and make V2 the subject because it's the one u are looking for ....