Answer:
8.62 g of Hydrogen
Solution:
Molar mass of CH₄O (Methanol) is 32 g.mol⁻¹.
It means,
32 g of CH₄O contains = 4 g of Hydrogen
Then,
69 g of CH₄O will contain = X g of Hydrogen
Solving for X,
X = (69 g × 4 g) ÷ 32 g
X = 8.62 g of Hydrogen
Answer:
It can be produced, 12 moles of MgO.
Option B
Explanation:
2 KClO₃ → 3O₂ + 2 KCl
Ratio in this reaction is 2:3
In the begining, I make 3 moles of oxygen, that came from 2moles of chlorate. If I have 4 moles of salt, let's make a rule of three.
2 moles of salt ___ make __3 moles of O₂
4 moles of salt ___ make (4 .3) /2 = 6 moles of O₂
2 Mg + O2 → 2 MgO.
From 1 mol of oxygen, I can make 2 moles of oxygen.
If I have 6 moles, I would make the double, though.
Answer:
12 moles of CO
Explanation:
According to Avogadro, one mole of a substance, contains the same number of elementary entities as 12g of carbon-12. Now the number of elementary entities (atoms, molecules, ions, particles etc) in any substance is given by the Avogadro's constant.
Now since 1 mole of a substance contains Avogadro's number of atoms, it means that the substance with the highest number of moles will have the highest number of atoms.
With this in mind we can see that 12 moles of CO is expected to contain 72.24 ×10^23 atoms of CO. Hence the answer.
They are called lanthanoids!