They speed up the breakdown of food in the stomach.
Answer:
(a) a = 5.08x10⁻⁸ cm
(b) r = 179.6 pm
Explanation:
(a) The lattice parameter "a" can be calculated using the following equation:
<em>where ρ: is the density of Th = 11.72 g/cm³, N° atoms/cell = 4, m: is the atomic weight of Th = 232 g/mol, Vc: is the unit cell volume = a³, and </em>
<em>: is the Avogadro constant = 6.023x10²³ atoms/mol. </em>
Hence the lattice parameter is:
![a = \sqrt[3]{1.32 \cdot 10^{-22} cm^{3}} = 5.08 \cdot 10^{-8} cm](https://tex.z-dn.net/?f=%20a%20%3D%20%5Csqrt%5B3%5D%7B1.32%20%5Ccdot%2010%5E%7B-22%7D%20cm%5E%7B3%7D%7D%20%3D%205.08%20%5Ccdot%2010%5E%7B-8%7D%20cm%20)
(b) We know that the lattice parameter of a FCC structure is:
<em>where r: is the atomic radius of Th</em>
Hence, the atomic radius of Th is:
I hope it helps you!
Carbon-14 is <span>radioactive element is used to determine the absolute age of late pleistocene animal remains because it is abundant in organic matter. Its decay is first-order and its half-life has been determined to be 5730 years which </span><span>means that after </span>5730 years, the amount of carbon<span>−</span>14<span> will be 1/2 of the initial amount.</span>
Answer:
The answer is
<h2>[OH-] = 1.66 × 10^-14 M</h2>
Explanation:
To find the [OH-] we must first find the pH and the pOH of the solution
That's
pH + pOH = 14
pOH = 14 - pH
To find the pH we use the formula
pH = -log [H3O+]
From the question
[H3O+] = 0.6 M
pH = - log 0.6
pH = 0.22
pOH = 14 - 0.22
pOH = 13.78
We can now find the [OH -] in the solution using the formula
pOH = - log [OH-]
13.78 = - log [OH-]
Find the antilog of both sides
We have the final answer as
<h3>[OH-] = 1.66 × 10^-14 M</h3>
Hope this helps you
