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VLD [36.1K]
3 years ago
15

Why is it not a good idea to use a stopper when combining two unknown substances in  test?

Chemistry
1 answer:
Colt1911 [192]3 years ago
6 0
Hi!

You would not want to use a stopper when<span> combining two unknown substances because the gasses made from the combination could end up creating to much pressure and explode.</span>
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Due to radioactive decay over many millions of years, it is possible for the element uranium to decay in
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The uranium within these items is radioactive and should be treated with care. Uranium's most stable isotope, uranium-238, has a half-life of about 4,468,000,000 years. It decays into thorium-234 through alpha decay or decays through spontaneous fission.

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Use Boyle's Law to explain what would happen to the volume of a helium- filled balloon if it was carried underwater by a diver t
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The deeper the diver takes the helium balloon, the more it reduces in size. This is due to the pressure of the water column above pressing on the balloon. According to Boyle’s law (P= k*1/V.), as the volume of the balloon decreases, the pressure of the helium inside increases.

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3 years ago
a. What condition must be met for an activated complex to result from the collision of reactant particles? b. Where, in terms of
weeeeeb [17]

Answer:

A. The conditions are:

I. Reactant particles must collide with the right orientation.

II. There must be effective collisions.

III. The reactant particles must possess enough energy to break old bonds so that new bonds can be formed.

B. The activated complex occurs where the maximum energy of the reaction is attained along the reaction pathway, that is, at the peak of the activation energy.

6 0
3 years ago
Two systems with heat capacities 19.9 J mol-1 K-1 and 28.2 ] mol 1 K-1 respectively interact thermally and come to an equilibriu
MAVERICK [17]

Answer : The initial temperature of system 2 is, 19.415^oC

Explanation :

In this problem we assumed that the total energy of the combined systems remains constant.

-q_1=q_2

m\times c_1\times (T_f-T_1)=-m\times c_2\times (T_f-T_2)

The mass remains same.

where,

C_1 = heat capacity of system 1 = 19.9 J/mole.K

C_2 = heat capacity of system 2 = 28.2 J/mole.K

T_f = final temperature of system = 30^oC=273+30=303K

T_1 = initial temperature of system 1 = 45^oC=273+45=318K

T_2 = initial temperature of system 2 = ?

Now put all the given values in the above formula, we get

-19.9J/mole.K\times (303-318)K=28.2J/mole.K\times (303-T_2)K

T_2=292.415K

T_2=292.415-273=19.415^oC

Therefore, the initial temperature of system 2 is, 19.415^oC

8 0
3 years ago
Help..................................................................:)
34kurt

Answer:

ppppp

Explanation:

4 0
3 years ago
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