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kow [346]
3 years ago
13

HHHHHHEEEEEEELLLLLPPPPPP MEH!!! PLS ANSWER QUICKLY! Brainliest!! y is inversely proportional to square of x. Given that y=4 when

x=3, find the value of y when x=5
Mathematics
1 answer:
artcher [175]3 years ago
7 0

Answer:

y = \frac{36}{25}

Step-by-step explanation:

y ∝ \frac{1}{x^2}

=> y = \frac{k}{x^2} --------------(1)

<u><em>Now, y = 4 and x = 3. </em></u>

<em>Putting in (1)</em>

=> 4 = \frac{k}{9}

=> k = 4*9

=> k = 36

<u><em>Now, y = ?, when x = 5</em></u>

<u><em>Putting in (1)</em></u>

=> y = \frac{36}{5^2}

=> y = \frac{36}{25}

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Answer:

Table 3

Step-by-step explanation:

Check table three;

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Since the left hand limit (lim\:_{x\to \:2^-}\:f\left(x\right)) is not equal to the right hand limit (lim\:_{x\to \:2^+}\:f\left(x\right)),  the limit as x approaches to 2 does not exist.

Therefore "nonexistent" is true, and table 3 is the correct model of the limits of the function at x = 2

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\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{-6})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{-4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-4}-\stackrel{y1}{(-6)}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{4}}}\implies \cfrac{-4+6}{4}\implies \cfrac{2}{4}\implies \cfrac{1}{2}

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Sunny_sXe [5.5K]

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