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2 years ago

I need help on my math I'M in K12

Mathematics

1 answer:

gizmo_the_mogwai [7]2 years ago

6 0

Total males: 45
Males who prefer Spring: 26/45, decimal: 0.578 rounded
Males who prefer Fall: 22/45, Decimal: 0.489 rounded
Total Females: 51
Females who prefer Spring: 22/51, Decimal: 0.431 rounded
Females Who prefer Fall: 29/51 , Decimal: 0.569 rounded
Hoped this help!!

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Grace's father gave her a nickel. If she had 64¢ before her father gave her the nickel, how much money did she have after gettin

emmainna [20.7K]

69 cents. 64 + 5 is 69.

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2 years ago

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(this is my sister on my acc I'm letting her) True or False? When you use a pulley you use less force to pull up a load.Explain

natta225 [31]

Answer:

True depending on what you are comparing it to.

Step-by-step explanation:

A pulley would help lighten the load that you are trying to pull up, which may make it easier for you to get the load to your designated area. The more complicated it is, usually the more 'lighter' it becomes, or the less force you have to exert.

For example, you will have to give a 100% energy in trying to life a heavy box. However, if you use a simple pulley (only one), you may only have to exert 75% more energy, for the weight is significantly lower.

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3 years ago

45 POINTS AND BRAINLIEST IF CORRECT

natita [175]

Answer:

2x+100

Step-by-step explanation:

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3 years ago

Math problem please help

PolarNik [594]

Step-by-step explanation:

Equations:

68.75 = 0.5c + 1.25m

c + m = 100

First, let's get rid of one of the variables. Let's start with the simplest equation first. Let's move a variable, so that only one variable is equal to the rest of the equation.

c + m = 100 to c = -m + 100

(it doesn't matter which variable)

Next, since we have what variable <em>c </em>is equal to, we will now incorporate it into our more complex equation.

68.75 = 0.5(-m + 100) + 1.25 m

Now, to get rid of the parentheses, and just have a regular addition equation with the only variable being <em>m.</em>

68.75 = -0.5m + 50 + 1.25m

Next, we need to make it so that there is only one version of the variables. Just combine the variables together so that the form one cohesive unit.

68.75 = 0.75m + 50

Now, we are going to do the same thing that we did in our first equation (with a mix of the last step we just did), but instead of variables, we are going to do it with the whole numbers instead, and converge them onto one side of the equal sign. Keep in mind that at this step in the process, the variable with it's cohesive unit should be isolated on one side of the equal sign and the other being taken up solely by whole numbers.

118.75 = 0.75m

Now, we just need to make the variable equal to 1 (or just <em>m</em>). So we must either multiply or divide. In this case we will be multiplying both sides by 0.75.

118.75 x 0.75 = 0.75m

So, after this step, you should have an answer of;

89.0625

However, you can't just sell a 0.0625% portion of something to somebody (especially muffins, like come on). Also, the amount of cookies and muffins must be equal to 100 and each variable is in whole numbers (usually).

*Always make sure that when you are done with a problem that you double check it. Usually, with equations like this, you just plug in the variables into the equations, and if they fit both equations, you've done well.

From this point forward, I'm leaving you to your own devices. It's 2:38 a.m. and I need to get up at 7:15. I hope this helps!

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2 years ago

If 13cos theta -5=0 find sin theta +cos theta / sin theta -cos theta

Ivahew [28]

Step-by-step explanation:

We have to find the value of (sinθ + cosθ)/(sinθ - cosθ), when 13 cosθ - 5 = 0.

$\red{\frak{Given}} \begin{cases} & \sf {13\ cos \theta\ -\ 5\ =\ 0\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \big\lgroup Can\ also\ be\ written\ as \big\rgroup} \\ & \sf {cos \theta\ =\ {\footnotesize{\dfrac{5}{13}}}} \end{cases}$

Here, we're asked to find out the value of (sinθ + cosθ)/(sinθ - cosθ), when 13 cosθ - 5 = 0. In order to find the solution we're gonna use trigonometric ratios to find the value of sinθ and cosθ. Let us consider, a right angled triangle, say PQR.

Where,

PQ = Opposite side
QR = Adjacent side
RP = Hypotenuse
∠Q = 90°
∠C = θ

As we know that, 13 cosθ - 5 = 0 which is stated in the question. So, it can also be written as cosθ = 5/13. As per the cosine ratio, we know that,

$\rightarrow {\underline{\boxed{\red{\sf{cos \theta\ =\ \dfrac{Adjacent\ side}{Hypotenuse}}}}}}$

Since, we know that,

cosθ = 5/13
QR (Adjacent side) = 5
RP (Hypotenuse) = 13

So, we will find the PQ (Opposite side) in order to estimate the value of sinθ. So, by using the Pythagoras Theorem, we will find the PQ.

Therefore,

$\red \bigstar {\underline{\underline{\pmb{\sf{According\ to\ Question:-}}}}}$

$\rule{200}{3}$

$\sf \dashrightarrow {(PQ)^2\ +\ (QR)^2\ =\ (RP)^2} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ +\ (5)^2\ =\ (13)^2} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ +\ 25\ =\ 169} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ =\ 169\ -\ 25} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ =\ 144} \\ \\ \\ \sf \dashrightarrow {PQ\ =\ \sqrt{144}} \\ \\ \\ \dashrightarrow {\underbrace{\boxed{\pink{\frak{PQ\ (Opposite\ side)\ =\ 12}}}}_{\sf \blue{\tiny{Required\ value}}}}$

∴ Hence, the value of PQ (Opposite side) is 12. Now, in order to determine it's value, we will use the sine ratio.

$\rightarrow {\underline{\boxed{\red{\sf{sin \theta\ =\ \dfrac{Opposite\ side}{Hypotenuse}}}}}}$

Where,

Opposite side = 12
Hypotenuse = 13

Therefore,

$\sf \rightarrow {sin \theta\ =\ \dfrac{12}{13}}$

Now, we have the values of sinθ and cosθ, that are 12/13 and 5/13 respectively. Now, finally we will find out the value of the following.

$\rightarrow {\underline{\boxed{\red{\sf{\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}}}}}}$

By substituting the values, we get,

$\rule{200}{3}$

$\sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ {\footnotesize{\dfrac{\Big( \dfrac{12}{13}\ +\ \dfrac{5}{13} \Big)}{\Big( \dfrac{12}{13}\ -\ \dfrac{5}{13} \Big)}}}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ {\footnotesize{\dfrac{\dfrac{17}{13}}{\dfrac{7}{13}}}}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{13} \times \dfrac{13}{7}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{\cancel{13}} \times \dfrac{\cancel{13}}{7}} \\ \\ \\ \dashrightarrow {\underbrace{\boxed{\pink{\frak{\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{7}}}}}_{\sf \blue{\tiny{Required\ value}}}}$

∴ Hence, the required answer is 17/7.

6 0

2 years ago