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enyata [817]
3 years ago
15

A small cylindrical has a diameter of 18mm and a height 12mm. Determine the minimum surface area of a box that can hold a row of

five candles
Mathematics
1 answer:
dimaraw [331]3 years ago
5 0

Answer:

The surface are of a box = 1186.92 mm²  

Step-by-step explanation:

Given in question as :

Diameter of cylinder = 18 mm

The height of cylinder = 12 mm

The surface area of cylinder = ( 2×\pi×r×h) + (2×\pi×r²)

where R is the radius , R = \frac{Diameter}{2}  = \frac{18}{2}

Or Radius r = 9 mm

Or, The surface area of cylinder= ( 2×\pi×9×12) + 2×\pi×(9)²)

Or , The surface area of cylinder=(678.24) + (508.68)

Or ,The surface area of cylinder= 1186.92 mm²

Hence the surface are of a box = 1186.92 mm²     Answer

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4. If TV = 14x - 8, find TU.<br> 9x+2 <br> 5
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<u><em>Answer:</em></u>

x = 3

<u><em>Explanation:</em></u>

The complete question is shown in the attached diagram

<u>Collinear points</u> are defined as points that lie on the same straight line

Since points U, T and V are given to be collinear, this means that these three points lie on the same straight line

Now, we are given that point U is between points T and V

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<u>Substitute with the givens in the above mentioned equation and solve for x as follows:</u>

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Hope this helps :)

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