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2 years ago

13

Rename .03 using other place values?

1 answer:

Kitty [74]2 years ago

7 0

Point three hundredth

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100 points please answer!

julia-pushkina [17]

Answer:

you don't have a question

Step-by-step explanation:

what is your question.

3 0

2 years ago

Read 2 more answers

I need help on math can u guys pick 6 random ones and help give me the answer plz

vladimir1956 [14]

Answer:
1. x^2-36
X^2-6^2
(X-6)•(x+6)

3. 16y^2-25
4^2 Y^2-5^2
(4y)^2-5^2
(4y-5)•(4y+5)

5. 9a^2-121
3^2 a^2-11^2
(3a)^2-11^2
(3a-11)•(3a+11)

6. 196-x^2
14^2 -x^2
(14-x)•(14+x)

8. 36c^2-d^2
6^2 c^2 -d^2
(6c)^2-d^2
(6c-d)•(6c+d)

11. 1-4a^2
1^2- 2^2 a^2
1^2-(2a)^2
(1-2a)•(1+2a)

3 0

2 years ago

Please help me with the below question.

VMariaS [17]

By letting

$y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}$

we get derivatives

$y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}$

$y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}$

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

$5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0$

Examine the lowest degree term $\left(x^{r-1}\right)$ , which gives rise to the indicial equation,

$5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0$

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients $c_k$ is

$(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}$

so that with r = 4/5, the coefficients are governed by

$c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}$

c) Starting with $c_0=1$ , we find

$c_1 = -\dfrac{c_0}5 = -\dfrac15$

$c_2 = -\dfrac{c_1}{10} = \dfrac1{50}$

so that the first three terms of the solution are

$\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}$

4 0

1 year ago

What is 2 to the power of 4/3 equal to

Reika [66]

Answer:

<h2><u>E</u><u>k</u>sponent</h2>

$\sf{ \large{ \boxed{ \red{ {a}^{ \frac{n}{m} } = \sqrt[m]{ {a}^{n} } } } }}$

$\sf{ {2}^{ \frac{4}{3} } }$

$= \sqrt[3]{ {2}^{4} }$

$= \sqrt[3]{2 \times 2 \times 2 \times 2}$

$= \boxed {\bold{\sqrt[3]{16}(c.) }}$

4 0

1 year ago

1. What is the measure of angle PSQ?<br><br> 80°<br> 140°

Anna11 [10]

140 degrees because an angle of a circle is 360 degrees and you can subtract these angles from it to get 140 degrees

3 0

2 years ago

Read 2 more answers