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yaroslaw [1]
3 years ago
10

Find the midpoint of the segment with the following endpoints(-8,-6) and (2,-10)

Mathematics
1 answer:
Aleks [24]3 years ago
4 0

Answer:

(-3, -8)

Step-by-step explanation:

-8+2/2= -3

-6 -10/2= -8

(-3, -8)

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Theresa’s computer at home has 1 terabyte of storage. How many more bits of storage does her computer have than the combined bit
posledela

Answer:

Not enough information provided

Step-by-step explanation:

To find the difference between one terabyte and the storage available to the other mediums, we would need to know the storage available to those mediums.  They can all have potentially different amounts of storage space, so we have no way to answer that part of the question.

We can however find out how many bits her computer has.  There are two lines of thought  to follow though.  kilo, mega, giga etc each generally note a multiple of 1000 in common terms.  In computer tech though, the number 1024, or 2¹⁰, is often used instead.

Starting with the layman's powers of 10, a terabyte is a thousand gigabytes, which in turn is a thousand megabytes, which is a thousand kilobytes, which is a thousand bytes.

That means that a terabyte stores 1 × 10¹² bytes.  A byte however is eight bits, giving us 8 × 10¹² bits.

Using the nerdier powers of 2 then, a byte is eight bits, so we'll call that 2³.  We then go up by multiples of 2¹⁰.  With the same logic above, a terabyte is 2¹⁰ gigabytes, which is 2¹⁰ megabytes, which is 2¹⁰ kilobytes, which is 2¹⁰ bytes.  Adding the exponents up, then a terabyte would be 2⁴³ bits

So depending on whether you use the powers of ten or powers of 2 conventions, then a terabyte is either 8 × 10¹² bits, or 2⁴³ bits.

If you want to express the latter as a power of ten for proper scientific notation, then it would be 8.796093022208 × 10¹² - a rather useless way of expressing it, but just to cover all bases.

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3 years ago
? What is the next step in the proof? Choose the most logical approach. Given: Transversal t passes through parallel lines r and
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Suppose that a family wants to increase the size of the garden which is currently 16 feet long and 8 feet wide without changing
Cloud [144]

Answer:

See below

Step-by-step explanation:

<u>Sides of the garden</u>

  • 16 feet and 8 feet

<u>New dimensions of the garden</u>

  • 16 + 2x and 8 + x

<u>1. The area of the new garden</u>

  • (16 + 2x)(8 + x) =
  • 2x^2 + 32x + 128

<u>2. The difference in area </u>

  • 2x^2 + 32x + 128 - 16*8 =
  • 2x^2 + 32x

<u>3. x= 2 effect on the area</u>

  • 2*2^2 + 32*2 =
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<u>4. Area difference = 160</u>

  • 2x^2 + 32x = 160
  • x^2 + 16x - 80 = 0
  • Solving we get positive root of 4 ft

<u>5. Area difference = 4 times</u>

  • 2x^2 + 32x = 128*3
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  • x^2 + 16x - 192= 0
  • Solving we get positive root of 8 ft

3 0
3 years ago
A floor is made up of 20 triangular tiles, each with sides 40 cm, 24 cm and 32 cm. Find the cost of polishing the floor at the r
pochemuha

Answer:

15360\,\,rupees

Step-by-step explanation:

Let sides of the triangle be a,b,c

a=40\,,\,b=24\,,\,c=32

Semi-perimeter (s) = \frac{a+b+c}{2}

=\frac{40+24+32}{2}\\ =\frac{96}{2}\\=48

Area of one tile =\sqrt{s(s-a)(s-b)(s-c)}

=\sqrt{48(48-40)(48-24)(48-32)}\\ =\sqrt{48(8)(24)(16)}\\ =\sqrt{147456} \\=384\,\,cm^2

So,

Area of 20 tiles =20(384)=7680\,\,cm^2

Cost of polishing the floor at the rate of 2 rupees per sq.cm = 7680(2)=15360\,\,rupees

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