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Nimfa-mama [501]
4 years ago
14

The graphed line shown below is y = negative 2 x minus 8. Which equation, when graphed with the given equation, will form a syst

em that has infinitely many solutions? y = negative (2 x + 8) y = negative 2 (x minus 8) y = negative 2 (x minus 4) y = negative (negative 2 x + 8)

Mathematics
2 answers:
aev [14]4 years ago
7 0

Answer: A y = -(2x+8)

Step-by-step explanation:

The first line is y=-2x-8

Thus, the answer that simplifies to y = -2x-8 is the answer.  

a) y=-(2x+8)

Distribute

y=-2x-8

Because it works, no need to try the others.

<em>Hope it helps <3</em>

Sophie [7]4 years ago
6 0

Answer:

\boxed{y = -(2x + 8)}

Step-by-step explanation:

For the two lines to have infinite \infty solutions, the two equations must be the same.

First equation : y = -2x - 8

A. y = -(2x + 8)

   y = -2x - 8 <em>correct</em>

<em />

B. y = -2(x - 8)

   y = -2x + 16 <em>incorrect</em>

C. y = -2(x - 4)

   y = -2x + 8 <em>incorrect</em>

D. y = -(-2x+8)

    y = 2x - 8 <em>incorrect</em>

<em />

y = -2x - 8 and y = -(2x + 8) when graphed are the same, they intersect at infinite points and there are infinite solutions.

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