Question

A survey of students' pets were taken. If {1}{4}" alt="\frac{1}{4}" align="absmiddle" class="latex-formula"> of the students had a dog only, 20% had a cat only, 15% had multiple pets, and 0.08 had pets other than cats or dogs. What fraction of the students did not have a pet? PLS SHOW WORK!

Answer 1

Answer:

32% of the students did not have a pet.

Step-by-step explanation:

From the total students (100%):

1. 1/4 of them had a dog only, $\frac{1}{4}=0.25=25\%$. Then, 25% had a dog only.
2. 20% only had a cat.
3. 15% had multiple pets.
4. 0.08=8% only had other than cats or dogs.
5. Adding up all these cases, we obtain the proportion of students that had at least one pet: $25\%+20\%+15\%+8\%=68\%$. Then, 68% of the students did have a pet.
6. The rest of the students $100\%-68\%=32\%$, did not have any pet.