Given:
- Bought n items of product A at 1/5 rs each
- bought n items of product B at 1/4 rs each
He mixed the two items and sold each at 2/9 rs each.
He lost 3 rs in the above batch of articles.
Solution:
revenue = 2n* (2/9) rs = 4n/9 rs
cost = n/5+n/4 rs = n(1/5+1/4)
Profit = revenue-cost = 4n/9-n(1/5+1/4) = -3 rs
Solve for n
4n/9-n(1/5+1/4) = -3
factor out n
n(4/9-1/5-1/4)=-3
n(80-36-45)/180=-3
-n/180=-3
n=3*180=540
Total number of products bought
= n+n = 540+540 = 1080
Answer:
64 cars
Step-by-step explanation:
total number of cars that the parking lot can hold = 8/3 × 24 = 64 cars
0.05 = 5% = 5/100
Simplify 5/100 and you get 1/20.
Hope this helps & good luck. :)
Answer:
We need an SRS of scores of at least 153.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find M as such
In which 
is the standard deviation of the population and n is the size of the sample.
How large an SRS of scores must you choose?
This is at least n, in which n is found when 
. So
Rounding to the next whole number, 153
We need an SRS of scores of at least 153.
Answer:
what are the answers or is it a paragrah you have to write
Step-by-step explanation:
