Answer:
Largest Median: Same
Largest Range: Castro
Largest IQR: Castro
Step-by-step explanation:
With a box-and-whisker plot, the box represents the upper and lower quartiles, the vertical line inside the box represents the median, and the lines on either side of the box show the high and low of the range.
Largest Median: Medians are the same because the verticle line inside the boxes is at 7 for both
Largest Range: Ms Castro's Class- the lines on either side of the box for Ms Castro go from 1-10 while the other class only goes from 4-10.
Largest IQR (interquartile range) Ms. Castro's class: their IQR goes from 5-8 while the other class only goes from 6-8
Answer:
3,876
Step-by-step explanation:
if you multiply 323 by 12 you get 2,876. Hope this helps!
Answer:
area: 41.04 cm² ; perimeter 35.8 cm
Step-by-step explanation:
Perimeter of shaded area = 1/4 perimeter of circle + line AC = ¼ * 3.14 * 2 * 12 + √(12² + 12²) = 18.84 + 12√2 cm = 35.8 cm
Area of Shaded Region = 1/4 area of circle - area of triangle = ¼ * 3.14 * 12² - ½ . 12 * 12
= (¼ * 3.14 - ½) * 12² = 41.04 cm²
Answer:
uhh either 4/4 1 or 2/2
Step-by-step explanation:
if the words covered by the light reflection says "the shaded part", then there are 4 total pieces, which means all four are shaded.
Answer:
Step-by-step explanation:
Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin) 
.
We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63
b = ±√(a² - c²)
= ±√(91² - 63²)
= ±√(8281 - 3969)
= ±√4312
= ±14√22
So the equation is
