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marshall27 [118]
3 years ago
8

Which sentence uses the correct adverb to make a comparison?

Physics
1 answer:
ss7ja [257]3 years ago
3 0
The answer to this would be c.
:) have a nice day 
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A person who weighs 509,45 N empties her lungs as much as
Masja [62]

Answer:

The weight of the girl = 1045.86 kg/m³

Explanation:

Density: This can be defined as the ratio of the mass of a body to the volume of that body. The S.I unit of density is kg/m³.

From Archimedes principle,

R.d = Density of the person/Density of water = Weight of the person in air/Upthrust.

⇒ D₁/D₂ = W/U............................... Equation 1.

Where D₁ = Density of the person, D₂ = Density of water, W = Weight of the person in air, U = Upthrust in water.

Making D₁ the subject of the equation,

D₁ = D₂(W/U)................................... Equation 2

<em>Given: D₂ = 1000 kg/m³ , W = 509.45 N, U = lost in weight = weight in air - weight in water = 509.45 - 22.34 = 487.11 N</em>

<em>Substituting these values into equation 2</em>

D₁ = 1000(509.45/487.11)

D₁ = 1045.86 kg/m³

Thus the weight of the girl = 1045.86 kg/m³

<em></em>

7 0
4 years ago
A puppy weighing 3 kilograms races through the dog park. If she slows from a speed of 2 meters/second to 1 meter/second, what wi
aliya0001 [1]
Ans: Thus, the kinetic energy change = 4.5 J

The mass of puppy = 3kg

Kinetic energy initial = \frac{1}{2} mv^{2}
                                   = \frac{1}{2}*3*4 = 6 kg-m/s2

Kinetic energy final = \frac{1}{2} mv^{2} = \frac{1}{2}*3*1 = 1.5 kg-m/s2

Thus, the kinetic energy change = 4.5 J
5 0
4 years ago
Read 2 more answers
Identify the characteristics of protists. Check all that apply.
romanna [79]

Answer:

There are no examples

Explanation:

3 1
3 years ago
Read 2 more answers
. In science, which of the following is NOT true about scientific theories a. They are generated by the testing of many hypothes
nydimaria [60]

Answer:

The correct option is  b) By the time they get to be theories, they cannot be disproven. It's not necessary that the theories are always right. They can be proven wrong.

Explanation:

5 0
4 years ago
An object of mass M oscillates on the end of a spring. To double the period, replace the object with one of mass: (a) 2M. (b)M/2
harkovskaia [24]

Answer:

(c) 4M

Explanation:

The system is a loaded spring. The period of a loaded spring is given by

T = 2\pi\sqrt{\dfrac{m}{k}}

<em>m</em> is the mass and <em>k</em> is the spring constant.

It follows that, since <em>k</em> is constant,

T\propto\sqrt{m}

\dfrac{T}{\sqrt{m}} = C where <em>C</em>  represents a constant.

\dfrac{T_1}{\sqrt{m_1}} = \dfrac{T_2}{\sqrt{m_2}}

m_2 = m_1\left(\dfrac{T_2}{T_1}\right)^2

When the period is doubled, T_2 = 2T_1.

m_2 = m_1\left(\dfrac{2T_1}{T_1}\right)^2 = 4m_1

Hence, the mass is replaced by 4M.

7 0
4 years ago
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