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Andrei [34K]
4 years ago
7

A puppy weighing 3 kilograms races through the dog park. If she slows from a speed of 2 meters/second to 1 meter/second, what wi

ll happen to her kinetic energy?
Physics
2 answers:
Tomtit [17]4 years ago
8 0

Answer: Kinetic energy will be decreases by 4.5 Joules.

Explanation:

Kinetic energy is the energy which is possessed by the virtue of objects motion. It is defined as the product of object's mass and square of the objects's velocity.

Mathematically,

K=\frac{1}{2}mv^2

Change in kinetic energy will be: K=\frac{1}[2}m\Delta v^2

where,

m = mass of the object = 3 kg

\Delta v=v_2-v_1 = Change in velocity

v_1=2m/s\\v=1m/s

Now, calculating the change in kinetic energy:

K.E.=\frac{1}{2}\times 3kg\times (1^2-2^2)m^2/s^2=-4.5J

Negative sign indicates that the kinetic energy is getting reduced.

Hence, kinetic energy will be decreases by 4.5 Joules.

aliya0001 [1]4 years ago
5 0
Ans: Thus, the kinetic energy change = 4.5 J

The mass of puppy = 3kg

Kinetic energy initial = \frac{1}{2} mv^{2}
                                   = \frac{1}{2}*3*4 = 6 kg-m/s2

Kinetic energy final = \frac{1}{2} mv^{2} = \frac{1}{2}*3*1 = 1.5 kg-m/s2

Thus, the kinetic energy change = 4.5 J
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  K_b = 78 J

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