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vladimir2022 [97]
4 years ago
5

The amount of dissolved oxygen that seawater can hold in solution will be greater in

Chemistry
1 answer:
kondaur [170]4 years ago
3 0
 the answer is "in cold water"
You might be interested in
The pH of 0.50 M benzoic acid is 2.24. Calculate the change in pH when 2.64 g of C6H5COONa is added to 38 mL of 0.50 M benzoic a
meriva

Answer:

1.93

Explanation:

Moles of C_{6}H_{5}COOH = 38/1000 × 0.50 = 0.019mol

Moles of C_{6}H_{5}COONa = Mass/Molar mass = 2.64/144.10 = 0.018321mol

Final pH = pKa + log([C_{6}H_{5}COONa]/[C_{6}H_{5}COOH]

= -log Ka  + log(mols of C_{6}H_{5}COONa]/mols of C_{6}H_{5}COOH

= -log(6.5 × 10^(-5)) + log (0.018321/0.019)=4.17

change in pH = final - initial pH

= 4.17 - 2.24

=1.93

5 0
4 years ago
A 0.2 M carboxylic acid (RCOOH) has a Ka = 1.66x10-6. What is the pH of this solution? Enter to 2 decimal places.
maria [59]

Answer:

3.24

Explanation:

The dissociation equation for the carboxylic acid can be represented as follows:

RCOOH —-> RCOO- + H+

We can use an ICE table to get the value of the concentration of the hydrogen ion. ICE stands for initial, change and equilibrium.

RCOOH RCOO- H+

Initial 0.2 0.0. 0.0

Change -x +x. +x

Equilibrium 0.2-x. x. x

We can now find the value of x as follows:

Ka = [RCOO-][H+]/[RCOOH]

(1.66* 10^-6) = (x * x)/(0.2-x)

(1.66 * 10^-6) (0.2-x) = x^2

x^2 = (3.32* 10^-7) - (1.66*10^-6)x

x^2 + (1.66 * 10^-6)x - (3.32* 10^-7) = 0

Solving the quadratic equation to get x:

x = 0.0005753650094369094 or - 0.0005753650094369094

As concentration cannot be negative, we discard the negative answer

Hence [H+] = 0.0005753650094369094

By definition, pH = -log[H+]

pH = -log(0.0005753650094369094)

pH = 3.24

8 0
3 years ago
What biological molecule that is used for energy is represented by the structure below?
Helga [31]

Answer:

Glucose. C6H12O6

Explanation:

In aerobic respiration glucose generate ATP. Which are the source of energy.

3 0
3 years ago
What are the characteristics of non-ideal solutions? a. The solute-solute and solvent- solvent interaction is different fromm th
finlep [7]

Answer:All the above

Explanation:

Non-ideal solutions are those solutions which do not obey Raoult's law in any conditions.

The molecular interactions of two components that is solute and solvent  are different.

If there are two components A and B then the molecular interaction between A-A,B-B would be different from the molecular interactions in A-B .

The enthalpy of mixing and volume of mixing for non-ideal solutions have  non zero values.

Enthalpy of mixing can be negative or positive in case of non-ideal solutions. If the enthalpy of mixing is negative so energy has been  released upon mixing the two components and if enthalpy of mixing is positive then energy is absorbed upon mixing the two components.

Non-ideal solutions are simply those solutions which are not ideal hence they should not be having the characterstics of ideal solutions.

For ideal solutions the molecular interactions between  the two components are equal.

So the molecular interaction between A-A,B-B  would be equal to the molecular interaction between A-B. Also the enthalpy of mixing and volume of mixing for ideal solutions are zero hence all the statements provided here are correctly charactersing non-ideal solutions.

4 0
4 years ago
A student heats a LaTeX: 2.5 g sample of calcium carbonate in a test tube. What mass of calcium oxide remains in the test tube w
polet [3.4K]

Answer:

2.5

Explanation:

3 0
3 years ago
Read 2 more answers
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