Question

There are 10 coins. 9 are fair and one is double-headed.

Answer 1

Answer:

0.050328

Step-by-step explanation:

Given that there are 10 coins, out of which 9 are fair and one is double headed.

P(selecting fair coin) = 0.9 and P(selecting double headed coin) = 0.1

P(H/fair coin)= 0.5 and P(H/doube headed ) = 1

Probability of getting in 1 toss head = Prob of selecting fair coin and getting head+ Prob of selecting double headed and getting head

= $0.9*0.5+0.1*1\\=0.55$

This will be constant p for 10 trials going to be done because coin is replaced each time.

Also there are only two outcomes

X no of heads in 5 flips is Binomial with (5, 0.55)

P(x=5) = Reqd probability

= $0.55^5\\=0.050328$