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3 years ago

8

mary mixes white paint with blue paint in the ratio 2:3. she makes a total of 20 litres of paint . how much more paint will she

need to add to the mixture so that the ratio of the white paint to blue paint will be 1:7

2 answers:

Anastasy [175]3 years ago

8 0

Mary has 20 liters of paint mixed white:blue in the ratio 2:3. So two fifths of that paint is white and three fifths is blue. So that's 8 liters white, 12 liters blue.

We want to add paint to get white:blue = 1:7. Clearly we need to add blue. We have our 8 liters of white, so we need a total of 7(8)=56 liters of blue. We already have 12, so we have to add 56-12=44 liters of blue paint:

Answer: Add 44 liters blue

snow_tiger [21]3 years ago

5 0

44 Litres

That’s the answer of what I got

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Can I get some help on these two

tia_tia [17]

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Answer:

cone: 138.16 in²

pyramid: 352 m²

Step-by-step explanation:

Use the appropriate formula from your list of area and volume formulas.

<u>Area of a Cone</u>

A = πr(r +h) . . . . . where r is the radius and h is the slant height

The radius is half the diameter, so is 4 inches.

A = π(4 in)(4 in + 7 in) = 44π in² ≈ 138.16 in²

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A = 2sh . . . . . where s is the side length of the base and h is the slant height

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2 years ago

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2 years ago

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3 years ago

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Is 11/2 and 6/11 equivalent? Plz I need the help☹️

trapecia [35]

For this case we have the following fractions:

$\frac {11} {2}\\\frac {6} {11}$

We must rewrite the fractions, using the same denominator.

We have then:

We multiply the first fraction by 11 in the numerator and denominator:

$\frac {11} {2} \frac {11} {11}$

We multiply the second fraction by 2 in the numerator and denominator:

$\frac {6} {11} \frac {2} {2}$

Rewriting we have:

For the first fraction:

$\frac {121} {22}$

For the second fraction:

$\frac {12} {22}$

We note that:

$\frac {121} {22}> \frac {12} {22}$

Answer:

The fractions are not equivalent:

$\frac {11} {2}> \frac {6} {11}$

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3 years ago

If sinA+cosecA=3 find the value of sin2A+cosec2A

Irina18 [472]

Answer:

$\sin 2A + \csc 2A = 2.122$

Step-by-step explanation:

Let $f(A) = \sin A + \csc A$ , we proceed to transform the expression into an equivalent form of sines and cosines by means of the following trigonometrical identity:

$\csc A = \frac{1}{\sin A}$ (1)

$\sin^{2}A +\cos^{2}A = 1$ (2)

Now we perform the operations: $f(A) = 3$

$\sin A + \csc A = 3$

$\sin A + \frac{1}{\sin A} = 3$

$\sin ^{2}A + 1 = 3\cdot \sin A$

$\sin^{2}A -3\cdot \sin A +1 = 0$ (3)

By the quadratic formula, we find the following solutions:

$\sin A_{1} \approx 2.618$ and $\sin A_{2} \approx 0.382$

Since sine is a bounded function between -1 and 1, the only solution that is mathematically reasonable is:

$\sin A \approx 0.382$

By means of inverse trigonometrical function, we get the value associate of the function in sexagesimal degrees:

$A \approx 22.457^{\circ}$

Then, the values of the cosine associated with that angle is:

$\cos A \approx 0.924$

Now, we have that $f(A) = \sin 2A +\csc2A$ , we proceed to transform the expression into an equivalent form with sines and cosines. The following trignometrical identities are used:

$\sin 2A = 2\cdot \sin A\cdot \cos A$ (4)

$\csc 2A = \frac{1}{\sin 2A}$ (5)

$f(A) = \sin 2A + \csc 2A$

$f(A) = \sin 2A + \frac{1}{\sin 2A}$

$f(A) = \frac{\sin^{2} 2A+1}{\sin 2A}$

$f(A) = \frac{4\cdot \sin^{2}A\cdot \cos^{2}A+1}{2\cdot \sin A \cdot \cos A}$

If we know that $\sin A \approx 0.382$ and $\cos A \approx 0.924$ , then the value of the function is:

$f(A) = \frac{4\cdot (0.382)^{2}\cdot (0.924)^{2}+1}{2\cdot (0.382)\cdot (0.924)}$

$f(A) = 2.122$

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