What is the equation of the translated function?

Which of the following points lies on the circle whose center is at the origin and whose radius is 10?

aliina [53]

The answer is (6,-8)

7 0

3 years ago

The CPA Practice Advisor reports that the mean preparation fee for 2017 federal income tax returns was $273. Use this price as t

skad [1K]

Answer:

a) 0.6212 = 62.12% probability that the mean price for a sample of 30 federal income tax returns is within $16 of the population mean.

b) 0.7416 = 74.16% probability that the mean price for a sample of 50 federal income tax returns is within $16 of the population mean.

c) 0.8804 = 88.04% probability that the mean price for a sample of 100 federal income tax returns is within $16 of the population mean.

d) None of them ensure, that one which comes closer is a sample size of 100 in option c), to guarantee, we need to keep increasing the sample size.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The CPA Practice Advisor reports that the mean preparation fee for 2017 federal income tax returns was $273. Use this price as the population mean and assume the population standard deviation of preparation fees is $100.

This means that $\mu = 273, \sigma = 100$

A) What is the probability that the mean price for a sample of 30 federal income tax returns is within $16 of the population mean?

Sample of 30 means that $n = 30, s = \frac{100}{\sqrt{30}}$

The probability is the p-value of Z when X = 273 + 16 = 289 subtracted by the p-value of Z when X = 273 - 16 = 257. So

X = 289

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{289 - 273}{\frac{100}{\sqrt{30}}}$

$Z = 0.88$

$Z = 0.88$ has a p-value of 0.8106

X = 257

$Z = \frac{X - \mu}{s}$

$Z = \frac{257 - 273}{\frac{100}{\sqrt{30}}}$

$Z = -0.88$

$Z = -0.88$ has a p-value of 0.1894

0.8106 - 0.1894 = 0.6212

0.6212 = 62.12% probability that the mean price for a sample of 30 federal income tax returns is within $16 of the population mean.

B) What is the probability that the mean price for a sample of 50 federal income tax returns is within $16 of the population mean?

Sample of 30 means that $n = 50, s = \frac{100}{\sqrt{50}}$

X = 289

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{289 - 273}{\frac{100}{\sqrt{50}}}$

$Z = 1.13$

$Z = 1.13$ has a p-value of 0.8708

X = 257

$Z = \frac{X - \mu}{s}$

$Z = \frac{257 - 273}{\frac{100}{\sqrt{50}}}$

$Z = -1.13$

$Z = -1.13$ has a p-value of 0.1292

0.8708 - 0.1292 = 0.7416

0.7416 = 74.16% probability that the mean price for a sample of 50 federal income tax returns is within $16 of the population mean.

C) What is the probability that the mean price for a sample of 100 federal income tax returns is within $16 of the population mean?

Sample of 30 means that $n = 100, s = \frac{100}{\sqrt{100}}$

X = 289

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{289 - 273}{\frac{100}{\sqrt{100}}}$

$Z = 1.6$

$Z = 1.6$ has a p-value of 0.9452

X = 257

$Z = \frac{X - \mu}{s}$

$Z = \frac{257 - 273}{\frac{100}{\sqrt{100}}}$

$Z = -1.6$

$Z = -1.6$ has a p-value of 0.0648

0.9452 - 0.0648 =

0.8804 = 88.04% probability that the mean price for a sample of 100 federal income tax returns is within $16 of the population mean.

D) Which, if any of the sample sizes in part (a), (b), and (c) would you recommend to ensure at least a .95 probability that the same mean is withing $16 of the population mean?

None of them ensure, that one which comes closer is a sample size of 100 in option c), to guarantee, we need to keep increasing the sample size.

6 0

2 years ago

I need help I’m helping my son with a project he has to choose 2 ingredients out of his Mac and cheese recipe and tell their rat

AnnyKZ [126]

Answer:

2/3:1

fillerfillerfillerfillerfiller

7 0

2 years ago

Between which two numbers is - 15 located on a number line?

sp2606 [1]

Answer:

21

Step-by-step explanation: 10+10+1=21

7 0

2 years ago

Help.. or die.. you decide.

Studentka2010 [4]

Answer:

Problem 1:

x = 12 unit ; y = 120 ; z = 60 ; perimeter = 58 unit

Problem 2:

FG = 16 unit ; EG = 2√153 unit ; y = 5 unit

Step-by-step explanation:

Problem 1

Since ABCD is a parallelogram. so,

∠ABC = ∠ADC [Since opposite angles of a parallelogram are equal]

but, ∠ADC = 120° [given]------------(1)

So, ∠ ABC = y° = 120° ----------------(2)

Again, sum of two consecutive angles of a parallelogram is, 180°, so,

∠BCD + ∠ADC = 180°

So, ∠BCD =z° = 180° - 120° = 60° [Putting the value of ∠ADC from (1)]-----(3)

Again, since opposite sides of a parallelogram are equal,

so, BC = AD

⇒ (x + 5) = 17

⇒ x = 12------------------------(4)

So, AB = 12 unit , AD = 17 unit

So, the perimeter of the parallelogram is given by,

2(AB + AD)

= $2 \times (12 + 17)$ unit

= 58 unit --------------------------------------------------------------(5)

Problem 2

Perimeter of parallelogram EFGH = 52 unit

So, 2(EH + GH) = 52 unit

⇒ 2 ( x + x + 6) = 52

⇒ 4x = 40

⇒ x = 10

Now, FG = EH [since opposite sides of a parallelogram are equal]

= (x + 6) unit

= (10 + 6) unit = 16 unit ------------------------------(1)

Again for a parallelogram, the diagonals bisect each other.

so, EG = $2 \times \sqrt{153}$

= 2√153 unit -----------------------------------------(2)

and,

3y - 10 = y

⇒ y = 5 -----------------------------------------------(3)

5 0

3 years ago