Answer:
y = -2, -9
Step-by-step explanation:
Hope this helps!
Answer:
2.4
Step-by-step explanation:
Answer:
TSA=6a²
TSA=6*17*17=1734 mm²
Step-by-step explanation:
Answer:
-2 5/9
Step-by-step explanation:
w + (-x) - 2/3
Let w = -5/9 and x = 4/3
-5/9 - 4/3 - 2/3
Get a common denominator
-5/9 -4/3*3/3 -2/3*3/3
-5/9 -12/9 -6/9
Add
-23/9
Change to a mixed number
-2 5/9
Answer;
The relevant probability is 0.136 so the value of 56 girls in 100 births is not a significantly high number of girls because the relevant probability is greater than 0.05
Step-by-step explanation:
The complete question is as follows;
For 100 births, P(exactly 56 girls = 0.0390 and P 56 or more girls = 0.136. Is 56 girls in 100 births a significantly high number of girls? Which probability is relevant to answering that question? Consider a number of girls to be significantly high if the appropriate probability is 0.05 or less V so 56 girls in 100 birthsa significantly high number of girls because the relevant probability is The relevant probability is 0.05
Solution is as follows;
Here. we want to know which of the probabilities is relevant to answering the question and also if 56 out of a total of 100 is sufficient enough to provide answer to the question.
Now, to answer this question, it would be best to reach a conclusion or let’s say draw a conclusion from the given information.
The relevant probability is 0.136 so the value of 56 girls in 100 births is not a significantly high number of girls because the relevant probability is greater than 0.05
