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3 years ago

A circle has the equation

Mathematics

1 answer:

Firlakuza [10]3 years ago

7 0

Answer:

choice G. (-5, 2)

Step-by-step explanation:

(x + 5)^2 + (y - 2)^2 = 9

(x + 5)^2 + (y - 2)^2 = 3^2

center( -5, 2)

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Mark Shaughnessy purchased a $4,250 bond at 91.50 that pays 7% interest. What was the cost of the bond?

Mrrafil [7]

Bond Cost=Face Value×Percent
Bond cost=4,250×0.915=3,888.75

3 0

3 years ago

Read 2 more answers

The electrician charges $50 per visit plus $12 per hour of work. Steve hires the electrician to do some work for his house. If S

TEA [102]

Answer:

12.5 hours

Step-by-step explanation:

budget: 200

fix cost: 50

hourly rate: 12

hours: ?

----

First we deduct the fix 50 dollars cost from the total budget.

Then we divide the remaining amount with the hourly rate

( 200 - 50 ) / 12 = ?

? = 12.5 hours

8 0

3 years ago

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$

The sample deviation for this case is s=30.23

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=9-1=8$

The Confidence interval is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and the critical values are:

$\chi^2_{\alpha/2}=20.09$

$\chi^2_{1- \alpha/2}=1.65$

And replacing into the formula for the interval we got:

$\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

Part b

For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

4 0

3 years ago

What is the slope of a line perpendicular to the line whose equation is<br> 2x – 2y = 20.

Simora [160]

Answer:

-1

Step-by-step explanation:

Solve for y into y=mx+b

2x-2y=20

-2y=-2x+20

y=(-2x+20)/-2

y=x-10

the slope is m, so it’s 1

A line perpendicular to that would be -1

7 0

3 years ago

A farm stand sells apples, a, for $5 a bucket and peaches, p,

Mrrafil [7]

Answer:

B. 5a + 8p = 155; p = a - 5

Step-by-step explanation:

4 0

3 years ago