Answer:
Is A ( -3,-6), (0,0),(3,6)
Answer: 15x + 6
5x + 2x+3 = 7x+3
6x+4 + 7x+3 = 13x + 7
13x+7 + 2x-1 = 15x+ 6
Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
![f(x)=x^{2}+8\:over\:[-1,4]](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B8%5C%3Aover%5C%3A%5B-1%2C4%5D)
1) Calculating the first derivative

2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function

3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.
Answer:
Are there two you're asking for?
#2: x ≥ 9
#3: x > -2
Step-by-step explanation:
#2 Work:
x - 13 ≥ -4
Step 1: Add 13 to both sides
x - 13 + 13 ≥ -4 + 13
Add -4 and 13 to get 9.
x ≥ 9
#3 Work:
x/2 > -1
Multiply both sides by 2. Since 2 is positive, the inequality direction remains the same
x/2 * 2 > -1 * 2
x > -2