two current carrying wires are placed next to each other. Their currents are moving in the same direction. Suggest why each wire
1 answer:
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Answer:
the induced current is
Explanation:
Given that :
side of the square (l) = 16 cm = 0.16 m
Magnetic field B = 0.750 y² t
Resistance R = 0.500 Ω
Time t = 0.490 s
Let consider a small rectangular; whose length is and breath is
Hence; to determine the magnetic flux through it small rectangular; we have:
Let calculate the total flux in the square loop
Thus the total flux in the square loop is
Now; going to the induced emf; let consider the Faraday's Law
Finally ; the induced current I is given by the expression;
Therefore; the induced current is
The correct answer is:
<span>Point charges must be in a vacuum.
In fact, the usual form for of the Coulomb's law is:
</span>
<span>where
</span>
is the permittivity of free space
<span>q1 and q2 are the two charges
q is the separation between the two charges
However, this formula is valid only if the charges are in vacuum. If they are in a material medium, the law is modified as follows:
</span>
where
is the relative permittivity, which takes into account the dielectric effects of the material.
<span>Point charges must be in a vacuum.
In fact, the usual form for of the Coulomb's law is:
</span>
<span>where
</span>
<span>q1 and q2 are the two charges
q is the separation between the two charges
However, this formula is valid only if the charges are in vacuum. If they are in a material medium, the law is modified as follows:
</span>
where