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Nikolay [14]
3 years ago
6

A 0.171-kilogram hockey puck is struck by a hockey stick. If the force from the hockey stick is 30.2 Newtons, but the puck also

experiences a force of friction of 3.5 Newtons at the same time, what is the acceleration of the puck?
Physics
1 answer:
Komok [63]3 years ago
4 0

Answer:

a = 156.14 m/s^2

Explanation:

Using the laws of newton:

∑F = ma  

where ∑F is the sumatory of forces, m the mass and a the aceleration.

so:

F -f_k = ma

where F is the force from the hockey stick and f_k is the force of friction.

Replacing values, we get:

(30.2N) - (3.5N)= (0.171kg)a

Finally, solving for a:

a = 156.14 m/s^2

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A car of mass 1000 kg is moving at 25 m/s. It collides with a car of mass 1200 kg moving at 30 m/s. When the cars collide, they
Alinara [238K]

Answer:

The total momentum of the cars before the collision is 61,000 kg.m/s

The total momentum of the cars after the collision is 61,000 kg.m/s

The velocity of the cars after the collision is 27.727 m/s

Explanation:

Given;

mass of the first car, m₁ = 1000 kg

initial velocity of the car, u₁ = 25 m/s

mass of the second car, m₂ = 1200 kg

initial velocity of the second car, u₂ = 30 m/s

The common velocity of the cars after collision = v

The total momentum of the cars before collision is calculated as;

P₁ = m₁u₁  +  m₂u₂

P₁ = (1000 x 25)  +  (1200 x 30)

P₁ = 61,000 kg.m/s

The total momentum of the cars after collision is calculated as;

P₂ = m₁v + m₂v

where;

v    is the common velocities of the cars after collision since they stick together.

P₂ = v(m₁ + m₂)

To determine "v" apply the principle of conservation of linear momentum for inelastic collision.

m₁u₁  +  m₂u₂  = v(m₁  + m₂)

(1000 x 25)  +  (1200 x 30) = v(1000 + 1200)

61,000 = 2,200v

v = 61,000/2,200

v = 27.727 m/s

The total momentum after collsion = v(m₁ + m₂)

                                                         = 27.727(1000 + 1200)

                                                          = 61,000 kg.m/s

Thus, momentum before and after collsion are equal.

8 0
2 years ago
some people agree that wearing seat belts reduces the risk of injurt to people in the car. however they say that the risk to oth
leva [86]

Answer:

It would be hard to test scientifically since it's subjective and can only be proven true if you conducted some experimentations and observations.

4 0
2 years ago
Calculate the speed of a car that traveled 200 kilometers in 3 hours.
nignag [31]

Answer:

The units (km/h) tell you how to do this! 200km/3h = 66.66666666…. BUT technically you only have ONE significant digit: 3 so 66.666… rounded to ONE digit is 70km/h but that is probably not important in this intro class so V = 66.67 or 67 km/h

8 0
2 years ago
Read 2 more answers
If I punch a wall, what is the Newton's 3rd Law Pair force?
UkoKoshka [18]
For every reaction, there is an equal and opposite reaction. This means that with every interaction, theres a pair of opposite forces on the object.
4 0
3 years ago
if the 50 kg object slows down to a velocity of 1 m/s how much kinetic energy does it have 100j 50j 25j or none
rodikova [14]

ek =  \frac{1}{2}m {v}^{2}

ek =  \frac{1}{2}(50) {(1)}^{2}

ek =  \frac{1}{2}(50)

ek = 25j

//

I'm not really sure but I do know that it's not 0 because the object is still moving, even if it's only moving at 1 m/s.

6 0
3 years ago
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