A 0.171-kilogram hockey puck is struck by a hockey stick. If the force from the hockey stick is 30.2 Newtons, but the puck also
1 answer:
Answer:
a = 156.14 m/s^2
Explanation:
Using the laws of newton:
∑F = ma
where ∑F is the sumatory of forces, m the mass and a the aceleration.
so:
F - = ma
where F is the force from the hockey stick and is the force of friction.
Replacing values, we get:
(30.2N) - (3.5N)= (0.171kg)a
Finally, solving for a:
a = 156.14 m/s^2
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Answer:
t=67.7s
Explanation:
From this question we know that:
Vo = 6m/s
a = 1.8 m/s2
D = 1500m
And we also know that:
Replacing the known values:
Solving for t we get 2 possible answers:
t1 = -44.3s and t2 = 67.7s Since negative time represents an instant before the beginning of the movement, t1 is discarded. So, the final answer is:
t = 67.7s
Answer:
The height of the building is 8,302.5 m
Explanation:
Given;
velocity of the projectile, u = 36 m/s
time of motion, t = 45 s
Let the upward direction of the bullet be negative,
The height of the building is calculated as;