All categories

3 years ago

When you eat fruit and vegetables chemical bonds of the release stored energy this is

Physics

2 answers:

Zinaida [17]3 years ago

5 0

Answer:

the energy is stored in the chemical bonds of both gas and food.

Explanation:

When your mother tells you to "eat your vegetables," there is a ... Chemical bonds in molecules of these nutrients contain energy. When the bonds are broken during digestion to form simpler molecules, the energy is released.

S_A_V [24]3 years ago

4 0

When you eat fruits and vegetables, chemical bonds are releasing stored energy, this is called chemical energy.

Hope this helps.

You might be interested in

Help ASAP). Draw additional masses to show how the block can be made to move toward point A. Be sure to draw the string and labe

chubhunter [2.5K]

Answer:

Given that the block have two applied masses 250 g at East and 100 g at South. In order to make a situation in which block moves towards point A, we have to apply minimum number of masses to the blocks. In order to prevent block moving toward East, we have to apply a mass at West, equal to the magnitude of mass at East but opposite in direction. Therefore, mass of 250 g at West is the required additional mass that has to be added. There is already 100 g of mass acting at South, that will attract block towards South or point A. No need to add further mass in North-South direction.

4 0

3 years ago

The author’s feeling about a subject or topic, which is evidenced in word choice, is called __________.

MatroZZZ [7]

The author’s feeling about a subject or topic, which is evidenced in word choice, is called tone. <span>They could be literal meanings which are meanings explicitly given to the readers or the person being told to. In this type of meaning, the person doesn’t need to think the words too much or ponder on the meaning because they could easily understand what the other person or the author implies. Meanwhile connotative meanings are meanings using different figures of speech or symbolism that the person still needs to think it over before knowing the actual meaning of the word, sentence or story.</span>

5 0

4 years ago

Read 2 more answers

An infinite line of charge with linear density λ1 = 8.2 μC/m is positioned along the axis of a thick insulating shell of inner r

bixtya [17]

1) Linear charge density of the shell: $-2.6\mu C/m$

2) x-component of the electric field at r = 8.7 cm: $1.16\cdot 10^6 N/C$ outward

3) y-component of the electric field at r =8.7 cm: 0

4) x-component of the electric field at r = 1.15 cm: $1.28\cdot 10^7 N/C$ outward

5) y-component of the electric field at r = 1.15 cm: 0

Explanation:

The linear charge density of the cylindrical insulating shell can be found by using

$\lambda_2 = \rho A$

where

$\rho = -567\mu C/m^3$ is charge volumetric density

A is the area of the cylindrical shell, which can be written as

$A=\pi(b^2-a^2)$

where

$b=4.7 cm=0.047 m$ is the outer radius

$a=2.7 cm=0.027 m$ is the inner radius

Therefore, we have :

$\lambda_2=\rho \pi (b^2-a^2)=(-567)\pi(0.047^2-0.027^2)=-2.6\mu C/m$

Here we want to find the x-component of the electric field at a point at a distance of 8.7 cm from the central axis.

The electric field outside the shell is the superposition of the fields produced by the line of charge and the field produced by the shell:

$E=E_1+E_2$

where:

$E_1=\frac{\lambda_1}{2\pi r \epsilon_0}$

where

$\lambda_1=8.2\mu C/m = 8.2\cdot 10^{-6} C/m$ is the linear charge density of the wire

r = 8.7 cm = 0.087 m is the distance from the axis

And this field points radially outward, since the charge is positive .

And

$E_2=\frac{\lambda_2}{2\pi r \epsilon_0}$

where

$\lambda_2=-2.6\mu C/m = -2.6\cdot 10^{-6} C/m$

And this field points radially inward, because the charge is negative.

Therefore, the net field is

$E=\frac{\lambda_1}{2\pi \epsilon_0 r}+\frac{\lambda_2}{2\pi \epsilon_0r}=\frac{1}{2\pi \epsilon_0 r}(\lambda_1 - \lambda_2)=\frac{1}{2\pi (8.85\cdot 10^{-12})(0.087)}(8.2\cdot 10^{-6}-2.6\cdot 10^{-6})=1.16\cdot 10^6 N/C$

in the outward direction.

To find the net electric field along the y-direction, we have to sum the y-component of the electric field of the wire and of the shell.

However, we notice that since the wire is infinite, for the element of electric field $dE_y$ produced by a certain amount of charge $dq$ along the wire there exist always another piece of charge $dq$ on the opposite side of the wire that produce an element of electric field $-dE_y$ , equal and opposite to $dE_y$ .

Therefore, this means that the net field produced by the wire along the y-direction is zero at any point.

We can apply the same argument to the cylindrical shell (which is also infinite), and therefore we find that also the field generated by the cylindrical shell has no component along the y-direction. Therefore,

$E_y=0$

Here we want to find the x-component of the electric field at a point at

r = 1.15 cm

from the central axis.

We notice that in this case, the cylindrical shell does not contribute to the electric field at r = 1.15 cm, because the inner radius of the shell is at 2.7 cm from the axis.

Therefore, the electric field at r = 1.15 cm is only given by the electric field produced by the infinite wire:

$E=\frac{\lambda_1}{2\pi \epsilon_0 r}$

where:

$\lambda_1=8.2\mu C/m = 8.2\cdot 10^{-6} C/m$ is the linear charge density of the wire

r = 1.15 cm = 0.0115 m is the distance from the axis

This field points radially outward, since the charge is positive . Therefore,

$E=\frac{8.2\cdot 10^{-6}}{2\pi (8.85\cdot 10^{-12})(0.0115)}=1.28\cdot 10^7 N/C$

For this last part we can use the same argument used in part 4): since the wire is infinite, for the element of electric field $dE_y$ produced by a certain amount of charge $dq$ along the wire there exist always another piece of charge $dq$ on the opposite side of the wire that produce an element of electric field $-dE_y$ , equal and opposite to $dE_y$ .

Therefore, the y-component of the electric field is zero.

Learn more about electric field:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

4 0

3 years ago

What is the mass of an object that has a 250 N force moving at an acceleration of 10 m/s2 ?

zzz [600]

Answer: 25 kg

Identify the given information.
f = 250 N
a = 10 m/s^2

Choose which formula you should use. In this case, you are finding the mass.
The formula for force is f = ma, so, using this, it is easy to find the mass.

f = ma Divide by a for both sides
m = f/a Formula for mass!

The formula for mass is m = f/a, where f is force and a is acceleration.

Substitute.
m = (250 N)/(10 m/s^2)
m = 25 kg

5 0

4 years ago

When the energy of a sound wave is transferred to a particle of a medium and causes it to vibrate and generate heat the sound wa

skelet666 [1.2K]

The answer of this said question is d

3 0

3 years ago

When you eat fruit and vegetables chemical bonds of the release stored energy this is​

When you eat fruit and vegetables chemical bonds of the release stored energy this is