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balu736 [363]
4 years ago
10

Will give brainliest and please show work

Mathematics
2 answers:
Tcecarenko [31]4 years ago
8 0
Let us break this figure into smaller shapes.

If you notice there are 4 small right triangles, one at each corner of the shape.
There are 2 small rectangles, one on the top and one on the bottom.
There is 1 big rectangle sitting in the middle.

One trick we can do to calculate the area faster is instead of saying 4 small triangles, we can say there are 2 small squares.
The reason we can do this is because all the triangles have a base length of 2 and a height of 2 also. If we put two triangles together they form a rectangle or square, but in this case it forms a square.

Now let's find the area of each of the small parts: small square, small rectangle, and big rectangle.
Remember: Area of rectangle =  length x width.

Area of 1 small square (made of two small triangles): It has a length of 2 units and a height of 2 units so each square's area is, 2 x 2 = 4 square units

Area of 1 small rectangle: It has a width of 2 units and a length of 6 units. The rectangle's area is 2 x 6 = 12 square units

Area of big rectangle: It has a width of 6 units and a length of 8 units. This means the big rectangle's area is 6 x 8 = 48 square units.

To find the area of the whole figure we add up all the small parts.

Area of 1 small square: 4 square units
Area of 1 small rectangle: 12 square units
Area of 1 big rectangle: 48 square units.

Note: We have 2 small squares, 2 small rectangles, and 1 big rectangle.

Total area of whole figure = 2(area of small square) + 2(area of small rectangle) + 1(area of big rectangle)


Total area of the figure is 80 square units.




daser333 [38]4 years ago
4 0
This will help u.............

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-3x-3y=3 ,y=-5x-17 solving systems by substitution
Law Incorporation [45]

Answer:

(-4, 3)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Solving systems of equations by substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

-3x - 3y = 3

y = -5x - 17

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                    -3x - 3(-5x - 17) = 3
  2. Distribute -3:                       -3x + 15x + 51 = 3
  3. Combine like terms:           12x + 51 = 3
  4. Isolate <em>x</em> term:                     12x = -48
  5. Isolate <em>x</em>:                              x = -4

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define equation:                    y = -5x - 17
  2. Substitute in <em>x</em>:                       y = -5(-4) - 17
  3. Multiply:                                  y = 20 - 17
  4. Subtract:                                 y = 3
8 0
3 years ago
*plz help it’s due tomorrow:)
ra1l [238]

Answer:

  • <em>The actual temperature after the freezer was on for five minutes could be </em><u><em>18ºF or 12ºF</em></u>

Explanation:

First, you must find the y-value returned by the line in the graph for a time (x) of five minutes, and then use the deviation of 3º to conclude the range of the real temperature.

<u>1. y- value at x = 5 min.</u>

The trend line (blue line in the graph) passes through the point (5,15), which means that it predicts a temperature of 15ºF when the time (x) is 5 minutes, or five minutes after the freezer was turned on.

<u>2. Actual temperature value</u>

It is stated that the temperature was actually three degrees from what the trend line shows, that means that the actual temperature could be 3ºF more or 3ºF less than the predicted temperature of 15ºF.

Mathematically:

  • Temperature = 15ºF ± 3ºF

  • Temparature = 15ºF + 3ºF or 15ºF - 3ºF

  • Temperature = 18ºF or 12ºF ← answer.
8 0
4 years ago
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