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balu736 [363]
3 years ago
10

Will give brainliest and please show work

Mathematics
2 answers:
Tcecarenko [31]3 years ago
8 0
Let us break this figure into smaller shapes.

If you notice there are 4 small right triangles, one at each corner of the shape.
There are 2 small rectangles, one on the top and one on the bottom.
There is 1 big rectangle sitting in the middle.

One trick we can do to calculate the area faster is instead of saying 4 small triangles, we can say there are 2 small squares.
The reason we can do this is because all the triangles have a base length of 2 and a height of 2 also. If we put two triangles together they form a rectangle or square, but in this case it forms a square.

Now let's find the area of each of the small parts: small square, small rectangle, and big rectangle.
Remember: Area of rectangle =  length x width.

Area of 1 small square (made of two small triangles): It has a length of 2 units and a height of 2 units so each square's area is, 2 x 2 = 4 square units

Area of 1 small rectangle: It has a width of 2 units and a length of 6 units. The rectangle's area is 2 x 6 = 12 square units

Area of big rectangle: It has a width of 6 units and a length of 8 units. This means the big rectangle's area is 6 x 8 = 48 square units.

To find the area of the whole figure we add up all the small parts.

Area of 1 small square: 4 square units
Area of 1 small rectangle: 12 square units
Area of 1 big rectangle: 48 square units.

Note: We have 2 small squares, 2 small rectangles, and 1 big rectangle.

Total area of whole figure = 2(area of small square) + 2(area of small rectangle) + 1(area of big rectangle)


Total area of the figure is 80 square units.




daser333 [38]3 years ago
4 0
This will help u.............

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8 0
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(8/5x² -2/3x³ +3/2x -1) - [ x/5x -3/2x² +2/3x +1/4]​
tia_tia [17]

Answer:

Step-by-step explanation:

4 0
3 years ago
At what point is the function y=(x+3)/(x^(2)-7x+12) continuous
nika2105 [10]

If a function is defined as

h(x)=\dfrac{f(x)}{g(x)}

where both f(x),g(x) are continuous functions, then h(x) is also continuous where defined, i.e. where g(x)\neq0

So, in your case, this function is continous everywhere, except where

x^2-7x+12=0

To solve this equation, we can use the formula x^2-sx+p=0

It means that, if the leading terms is 1, then the x coefficient is the opposite of the sum of the roots, and the constant term is the product of the roots.

So, we're looking for two terms whose sum is 7, and whose product is 12. These numbers are easily found to be 3 and 4.

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3 0
3 years ago
Find domain and range -√x-5+10
inysia [295]
When finding the domain of a square root, you have to know that it is impossible to get the square root of 0 or any negative number. since domain is possible x values this means that x cannot be 0 or any number less than 0. However, you can find the square root of the smallest most infinitely small number greater than 0. since an infinitely small number close to zero can not be written out, we must must say that the domain starts at 0 exclusive. exclusive is represented by an open or close parenthesis so in this case the domain starts with:
(0,
we can get the square root of any number larger than 0 up to infinity but infinity can never be reached so it is also exclusive. So so the ending of our domain would be:
,infinity)
So the answer if the square root is only over the x the answer is
(0, infinity)

But if the square root is over the x- 5 then this would brIng a smaller amount of possible x values. since anything under the square root sign has to be greater than 0, you can say that:
(x - 5) > 0
x > 5
Therefore the domain would start at 5 and the answer would be:
(5, infinity)
8 0
3 years ago
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