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balu736 [363]
3 years ago
10

Will give brainliest and please show work

Mathematics
2 answers:
Tcecarenko [31]3 years ago
8 0
Let us break this figure into smaller shapes.

If you notice there are 4 small right triangles, one at each corner of the shape.
There are 2 small rectangles, one on the top and one on the bottom.
There is 1 big rectangle sitting in the middle.

One trick we can do to calculate the area faster is instead of saying 4 small triangles, we can say there are 2 small squares.
The reason we can do this is because all the triangles have a base length of 2 and a height of 2 also. If we put two triangles together they form a rectangle or square, but in this case it forms a square.

Now let's find the area of each of the small parts: small square, small rectangle, and big rectangle.
Remember: Area of rectangle =  length x width.

Area of 1 small square (made of two small triangles): It has a length of 2 units and a height of 2 units so each square's area is, 2 x 2 = 4 square units

Area of 1 small rectangle: It has a width of 2 units and a length of 6 units. The rectangle's area is 2 x 6 = 12 square units

Area of big rectangle: It has a width of 6 units and a length of 8 units. This means the big rectangle's area is 6 x 8 = 48 square units.

To find the area of the whole figure we add up all the small parts.

Area of 1 small square: 4 square units
Area of 1 small rectangle: 12 square units
Area of 1 big rectangle: 48 square units.

Note: We have 2 small squares, 2 small rectangles, and 1 big rectangle.

Total area of whole figure = 2(area of small square) + 2(area of small rectangle) + 1(area of big rectangle)


Total area of the figure is 80 square units.




daser333 [38]3 years ago
4 0
This will help u.............

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The length of a rectangle is four feet longer than the width. the area is 21. find the dimension
MakcuM [25]
The length is 7 and the width is 3
7 0
2 years ago
How do I solve 1 and 2?
LuckyWell [14K]
H=+15 m
v=+5 m/s
Ball hits the ground when h(t)=-15m
h(t)=-9.8t^2+vt+h
=>
-15=-9.8t^2+5t+15
9.8t^2-5t-30=0
Solve for t, using quadratic formula,
t=-1.513 or t=2.023
reject negative root due to context, so
t=2.023 seconds

2)
h(t)=-16t^2+20t+8
a. height before pitch is when t=0, or h(0)=8
b. highest point reached when h'(t)=-32t+20=0 => t=5/8 seconds
c. highest point is t(5/8)=-16(5/8)^2+20(5/8)+8=47/5=9.4 m
d. ball hits ground when h(t)=0 => solve t for h(t)=0
=> t=-0.3187 seconds or t=1.569 seconds.
Reject negative root to give
time to hit ground = 1.569 since ball was pitched.

5 0
2 years ago
The solution to #68 and #70
atroni [7]
The trick is to write appropriate equations and then solve the system of equations you've created.

"sum of two numbers is -5:"  x + y = -5

"difference                   is  -1:"  x-y = -1

Add these two equations together.  This will cause y to drop out, and you will be left with an equation in x alone:

2x  = - 6, so x = -3.  Subst. -3 for x in either equation, above, and find the corresponding y value.

Then write your solution as (-3, y ) (write in your value for y).
8 0
3 years ago
If 12 +22+ 32 +
kakasveta [241]

Answer:

m2

Step-by-step explanation:

the 2nd equation is double the first one and the first one is 1

8 0
1 year ago
Write an equation that is parallel to y=2x +3 but passes through (2,-4)
I am Lyosha [343]
A parallel line is where you slope is the same but a different y-intercept.

y = 2x + 4
7 0
2 years ago
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