If y = √(2x + 1), then differentiating both sides implicitly with respect to t gives
dy/dt = 1/2 • 1/√(2x + 1) • 2 • dx/dt = 1/√(2x + 1) • dx/dt
(a) If dx/dt = 9 and x = 4, then
dy/dt = 1/√(2•4 + 1) • 9
dy/dt = 1/√(8 + 1) • 9
dy/dt = 1/√9 • 9
dy/dt = 9/3
dy/dt = 3
(b) If dy/dt = 3 and x = 40, then
3 = 1/√(2•40 + 1) • dx/dt
3 = 1/√(80 + 1) • dx/dt
3 = 1/√81 • dx/dt
3 = 1/9 • dx/dt
dx/dt = 27
First computer takes x min. For 1 min it does 1/x part of work.
Second computer takes (x+24) min. For one min it does 1/(x+24) part of work.
Both computers for one min do (1/x+1/(x+24)) part of work.
At the same time, both computers for one min do 1/9 part of work.
A. Or B.
I picked this in one of my questions and I don’t remember which specific one but the one or other should be correct.
<u><em>The answer is 11/12.</em></u>
<u><em>I got the answer by subtracting 5/4-1/3 and the answer would be the answer to the problem.</em></u>
<u><em>Hope this helps!</em></u>
<u><em>:)</em></u>
<span>f(x)=-x^2+10x+6
f(x)=3x^2-12x+9
f(x)=-2x^2+2x+7
f(x)=8-x^2 </span>