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Digiron [165]
3 years ago
5

Kelvin is the base unit of which pysical quantity?

Physics
2 answers:
KiRa [710]3 years ago
5 0
<h2>Answer:</h2><h2><em>Temperature</em></h2>

<h3><em>About </em><em>physical </em><em>quantities</em><em>:</em></h3>

<em>Those </em><em>quantities </em><em>which </em><em>can </em><em>be </em><em>measured </em><em>directly</em><em> </em><em>or </em><em>indirectly</em><em> </em><em>is </em><em>called </em><em>physical </em><em>quantities</em><em>.</em>

<em>There </em><em>are </em><em>two </em><em>types </em><em>of </em><em>physical</em><em> </em><em>quantities.They </em><em>are:</em>

  • <em>fundamental </em><em>quant</em><em>i</em><em>t</em><em>y</em>

<em>Those </em><em>quantity </em><em>which </em><em>are </em><em>not </em><em>dependent</em><em> </em><em>upon </em><em>any </em><em>qua</em><em>n</em><em>t</em><em>i</em><em>t</em><em>y</em><em> </em><em>are </em><em>called </em><em>fundamental</em><em> </em><em>quantity</em><em>.</em><em>f</em><em>o</em><em>r</em><em> </em><em>eg:</em><em> </em><em>length,</em><em>mass </em><em>time </em><em>etc.</em>

  • <em>Derived </em><em>Quantity</em>

<em>Those </em><em>quantity</em><em> </em><em>which </em><em>are </em><em>dependent</em><em> upon</em><em> </em><em>other </em><em>quantities </em><em>are </em><em>called </em><em>derived </em><em>Quantity. </em><em>for </em><em>eg:</em><em> </em><em>volume,</em><em>area </em><em>etc.</em>

<h2><em>About </em><em>temperature</em><em>:</em></h2>

<em>Temperature</em><em> </em><em>is </em><em>the </em><em>degree </em><em>of </em><em>hotness </em><em>and </em><em>coldness </em><em>of </em><em>a </em><em>body.Temperature </em><em>is </em><em>measured </em><em>in </em><em>degree,</em><em>Celsius,</em><em>degree </em><em>Fahrenheit</em><em> </em><em>or </em><em>Kelvin </em><em>scale.Temperature </em><em>is </em><em>measured </em><em>by </em><em>using </em><em>thermometer</em><em>.</em>

<em>Hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

KatRina [158]3 years ago
3 0

Answer:

<h2>Thermodynamic temperature</h2>

Explanation: Research states that ;

Thermodynamic temperature is the measure ( absolute)  of temperature and is one of the principal parameters of thermodynamics.

It uses the kelvin scale for measurement and selects the triple point of water at 273.16 K as the fundamental fixing point.

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A.) If its booster rockets accelerate the space shuttle at 15m/s2, how high will it be one minute after launch?
poizon [28]

Answer:

27,000 m

450 m/s

Explanation:

Assuming the initial velocity is 0 m/s:

v₀ = 0 m/s

a = 15 m/s²

t = 60 s

A) Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (60 s) + ½ (15 m/s²) (60 s)²

Δy = 27,000 m

B) Find: v_avg

v_avg = Δy / t

v_avg = 27,000 m / 60 s

v_avg = 450 m/s

5 0
3 years ago
A man stands on a platform that is rotating at 3.8 rpm; his arms are outstretched and he holds a brick in each hand. The rotatio
Ierofanga [76]

Answer:

a) 5.197rev/s

b) Kf/Ki =2.28

Explanation:

a) Angular momentum of the system L = Iw

ButLi=Lf

Kiwi =Ifwf

wf = (Ii/If)will = (4.65/3.4)×3.8=5.197rev/s

b)Kinetic energy KE= 0.5Iw^2

Ki = 0.5Iiwi^2

Kf=0.5Ifwf^2

Kf/Ki = Ifwf/Iiwi

Kf/Ki = (4.65/3.4))(5.197/3.8)

Kf/Ki = 1.22(1.368)^2

Kf/Ki = 2.28

8 0
3 years ago
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Answer:

d

Explanation:

7 0
3 years ago
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Una ave vuela a una velocidad constante de 15m/s en una trayectoria rectilínea. Si dura una hora volando ¿cuanta distancia habrá
earnstyle [38]

Answer:

54,000

Explanation:

3 0
3 years ago
1. The Moon's mass is 7.34 x 1022 kg, and it is 3.8 x 105 km away from Earth. Earth's
sineoko [7]

Answer:

2.03 x 10²⁴N

Explanation:

Given parameters:

Mass of moon = 7.34 x 10²²kg

Mass of the earth  = 5.97 x 10²⁴kg

Distance  = 3.8 x 10⁵km

Unknown:

Gravitational force of attraction  = ?

Solution:

To find the gravitational force of attraction between the masses, we use the expression below;

   F = \frac{Gm_{1} m_{2}  }{r^{2} }

G is the universal gravitation constant

m is the mass

1 and 2 represents moon and earth

r is  the distance

  F = \frac{6.67 x 10^{-11}  x 7.34 x 10^{22} x 5.97 x 10^{24}  }{(3.8 x 10^{5})^{2}  }

 F = \frac{2.92 x 10^{35} }{1.44 x 10^{11} }  = 2.03 x 10²⁴N

8 0
3 years ago
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