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3 years ago

Give two examples of when you would need to use the measure skill in science?

1 answer:

6 0

I'm guessing "measure skill" means "the ability to measure things." In reality, all experiments by necessity require data and typically we need to measure things to get them (even if this is done by devices, programs or computers). When doing science labs, you'll likely need to use scales, pipets, and various glasswear to measure different things. Even if you're used to using a ruler, getting a really good measurement that you can feed into equations and get meaningful results from requires a bit of practice and more care than you might think. I'd also say that the measurement skill comes into play when making approximations or assumptions about experiment. No measurement is infinitely accurate, you can't measure the width of an atom with a standard 12 inch ruler, or if you did, you'd have to have a very large amount of error. Making these logical conclusions about your devices, where they reach their limits, and what potential error you may have and where it comes from are all important when doing science.

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A disc on a frictionless axle, starting from rest (0 rpm) can spin up to a rotation rate of 3820 rpm in a period of 2 seconds. (

Eddi Din [679]

Answer:

1000 Nm

2000 Nm

1.00007 seconds

Explanation:

I = Moment of inertia = 5 kgm²

$\alpha$ = Angular acceleration

$\omega_f$ = Final angular velocity

$\omega_i$ = Initial angular velocity

t = Time taken

Torque is given by

$\tau=I\alpha\\\Rightarrow \tau=5\times 200\\\Rightarrow \tau=1000\ Nm$

The torque of the disc would be 1000 Nm

If $\alpha=400\ rad/s^2$

$\tau=I\alpha\\\Rightarrow \tau=5\times 400\\\Rightarrow \tau=2000\ Nm$

The torque of the disc would be 2000 Nm

From equation of rotational motion

$\omega_f=\omega_i+\alpha t\\\Rightarrow t=\frac{\omega_f-\omega_i}{\alpha}\\\Rightarrow t=\frac{3820\times \frac{2\pi}{60}-0}{400}\\\Rightarrow t=1.00007\ s$

It would take 1.00007 seconds to reach 3820 rpm

6 0

4 years ago

An insulating plastic rod is charged by rubbing it with a wool cloth, and then brought to an initially neutral conducting metall

barxatty [35]

Answer:

A) is repelled by the sphere.

Explanation:

When a charged insulated rod is touched with an insulated conducting sphere , some charge on the rod gets transferred to the sphere . So they become similarly charged . We all know that there is repulsion when two similarly charged object are brought near to each other . Hence here too there will be repulsion between the rod and the sphere when the rod is brought near the sphere.

3 0

3 years ago

Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.23 2.23 times a second. A tack is stuck in the t

elena-14-01-66 [18.8K]

Explanation:

The given data is as follows.

Angular velocity ( $\omega$ ) = 2.23 rps

Distance from the center (R) = 0.379 m

First, we will convert revolutions per second into radian per second as follows.

= 2.23 revolutions per second

= $2.23 \times 2 \times 3.14 rad/s$

= 14.01 rad/s

Now, tangential speed will be calculated as follows.

Tangential speed, v = $R \times \omega$

= 0.379 x 14.01

= 5.31 m/s

Thus, we can conclude that the tack's tangential speed is 5.31 m/s.

8 0

3 years ago

A tuning fork with a frequency of 675 Hz resonates in an air column when the length of the tube is 17.0 cm and again when the le

maria [59]

Answer:

Explanation:

8 0

3 years ago

When a driver presses the brake pedal, his car can stop with an acceleration of 5.4 m/s2. How far will the car travel while comi

notsponge [240]

$Given:\\a=5.4 \frac{m}{s^2} \\v_0= 25\frac{m}{s} \\\\Find:\\s=?\\\\Solution:\\\\s=v_0t- \frac{at^2}{2} \\\\a= \frac{\Delta v}{t} \\\\v_e=0\Rightarrow \Delta v=v_0\\\\t= \frac{v_0}{a} \\\\s= \frac{v_0^2}{a} - \frac{v_0^2}{2a} =\frac{v_0^2}{2a} \\\\s= \frac{ (25\frac{m}{s})2 }{2\cdot 5.4 \frac{m}{s^2} } \approx 57.9m\\\\C\rightarrow Correct\;answer$

3 0

3 years ago