HELP PLEASE I NEED THE ANSWERS FAST (15 POINTS)
1 answer:
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Answer:
15.6m/s
Explanation:
V1= because the derivate of the position is the velocity
V1=12t+3
V2=20+-8t because the integral of the acceleration is the velocity
V2=
V1=V2 to see when the velocities of particles match
12t+3=20-4t^2
4t^2+12t-17=0 we resolve this with
and we take the positif root
t=1.05 sec
if we evaluate the velocity (V1 or V2) the result is 15.6m/s
Answer:
4.53 second, 195 ft/s
Explanation:
u = 50 ft/s
h = 555 ft
g = 32 ft/s^2
Let the time taken by the ball to reach the ground is t and the velocity of the ball as it hits the ground is v.
Use third equation of motion
v = 195 ft /s
Thus, the ball strikes the ground with velocity 195 ft/s.
Use first equation of motion
v = u + at
195 = 50 + 32 t
32 t = 145
t = 4.53 second
Thus, the ball reach the ground in 4.53 second.