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8090 [49]
3 years ago
10

If this speed is based on what would be safe in wet weather, estimate the radius of curvature for a curve marked 50 km/h . The c

oefficient of static friction of rubber on wet concrete is μs=0.7, the coefficient of kinetic friction of rubber on wet concrete is μk=0.5.
Physics
1 answer:
PtichkaEL [24]3 years ago
7 0

Answer:

Explanation:

v = 50 km / h

= 13.89 m /s

When a vehicle runs on a circular path , it is static friction which prevents it from getting overturned .

static friction = μs mg

centripetal force = m v² / R

m v² / R = μs mg

R = v² / μs x g

= 13.89² / .7 x 9.8

= 28.12 m .

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Answer:

E=14.4\ J

Explanation:

In this case the kinetic energy of the bike is converted into the heat energy between the area of contact of tyre and the road. This happens due to the work done by the frictional force between the surface to stop the relative motion between the road and the tyre.

Given:

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(as given in the question that the rear tyre supports half the combined weight of the bike and the rider.)

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<u>Now, frictional force between the surfaces:</u>

f=\mu.N

f=0.8\times 45

f=36\ N

<u>Now, the work done by the kinetic friction:</u>

W=f.s

W=36\times 0.4

W=14.4\ J

According to the energy conservation this amount of energy is converted into thermal energy between the surfaces in contact, i.e. road and the tyre.

5 0
3 years ago
Martha (50 kg) is attracted to Stewart (70 Kg) who sits 4 m away. What is the gravitational attraction between them? G=6.67 x 10
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Answer:

1.46× 10^-8 N

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F=Gm₁m₂/r²

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Hope, this helps you.

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A ball is thrown straight up with an initial speed of 36 m/s . Part A How much time does it take for the ball to reach the top o
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Given

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Answer:

b. active solar heating systems

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