If this speed is based on what would be safe in wet weather, estimate the radius of curvature for a curve marked 50 km/h . The c
1 answer:
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Answer:
ar = 5.86*10^-3 m/s^2
Explanation:
In order to calculate the radial acceleration of the Earth, you first take into account the linear speed of the Earth in its orbit.
You use the following formula:
(1)
G: Cavendish's constant = 6.67*10^-11 m^3 kg^-1 s^-2
Ms: Sun's mass = 1.98*10^30 kg
r: distance between Sun ad Earth = 1.50*10^8 km = 1.50*10^11 m
Furthermore, you take into account that the radial acceleration is given by:
(2)
You replace the equation (1) into the equation (2) and replace the values of all parameters:
The radial acceleration of the Earth, towards the sun is 5.86*10^-3 m/s^2
Answer:
Final velocity, v = 0.28 m/s
Explanation:
Given that,
Mass of the model,
Speed of the model,
Mass of another model,
Initial speed of another model,
To find,
Final velocity
Solution,
Let V is the final velocity. As both being soft clay, they naturally stick together. It is a case of inelastic collision. Using the conservation of linear momentum to find it as :
V = 0.28 m/s
So, their final velocity is 0.28 m/s. Hence, this is the required solution.